The equation of a parabola is y=x2−8x+25. Write the equation in vertex form.Write any numbers as integers or simplified proper or improper fractions.______
Q. The equation of a parabola is y=x2−8x+25. Write the equation in vertex form.Write any numbers as integers or simplified proper or improper fractions.______
Identify Vertex Form: Identify the vertex form of a parabola. The vertex form of a parabola is given by y=a(x−h)2+k, where (h,k) is the vertex of the parabola.
Complete Square Transformation:Complete the square to transform the given equation into vertex form.The given equation is y=x2−8x+25. To complete the square, we need to find the value that makes x2−8x a perfect square trinomial. This value is (28)2=42=16. We will add and subtract this value inside the equation.
Add/Subtract Value: Add and subtract the value found in Step 2 to the equation.y=x2−8x+25y=x2−8x+16+25−16We added and subtracted 16 to complete the square without changing the value of the equation.
Rewrite Equation: Rewrite the equation by grouping the perfect square trinomial and combining the constants.y=(x2−8x+16)+(25−16)y=(x−4)2+9Now the equation is in vertex form, where (x−4)2 is the perfect square trinomial and 9 is the combined constant.
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