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The equation of a parabola is y=x2+8x+21y = x^2 + 8x + 21. Write the equation in vertex form.\newlineWrite any numbers as integers or simplified proper or improper fractions.\newline______

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Q. The equation of a parabola is y=x2+8x+21y = x^2 + 8x + 21. Write the equation in vertex form.\newlineWrite any numbers as integers or simplified proper or improper fractions.\newline______
  1. Identify vertex form: Identify the vertex form of a parabola.\newlineThe vertex form of a parabola is given by the equation y=a(xh)2+ky = a(x - h)^2 + k, where (h,k)(h, k) is the vertex of the parabola.
  2. Complete the square: Complete the square to rewrite the given equation in vertex form.\newlineWe start with the given equation y=x2+8x+21y = x^2 + 8x + 21. To complete the square, we need to find the value that makes x2+8xx^2 + 8x a perfect square trinomial. We do this by taking half of the coefficient of xx, squaring it, and adding it to and subtracting it from the equation. The coefficient of xx is 88, so half of 88 is 44, and 44 squared is 1616. We add and subtract 1616 to the equation.
  3. Add and subtract: Add and subtract 1616 to the equation.\newliney=x2+8x+16+2116y = x^2 + 8x + 16 + 21 - 16\newlineNow we have the perfect square trinomial x2+8x+16x^2 + 8x + 16 and the constants 2121 and 16-16.
  4. Factor and simplify: Factor the perfect square trinomial and simplify the constants.\newliney=(x+4)2+2116y = (x + 4)^2 + 21 - 16\newliney=(x+4)2+5y = (x + 4)^2 + 5\newlineNow the equation is in vertex form, where (h,k)=(4,5)(h, k) = (-4, 5).

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