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The equation of a parabola is y=x26x+5y = x^2 - 6x + 5. Write the equation in vertex form.\newlineWrite any numbers as integers or simplified proper or improper fractions.\newline______

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Q. The equation of a parabola is y=x26x+5y = x^2 - 6x + 5. Write the equation in vertex form.\newlineWrite any numbers as integers or simplified proper or improper fractions.\newline______
  1. Identify vertex form: Identify the vertex form of a parabola.\newlineThe vertex form of a parabola is given by y=a(xh)2+ky = a(x - h)^2 + k, where (h,k)(h, k) is the vertex of the parabola.
  2. Complete the square: Complete the square to transform the given equation into vertex form.\newlineWe start with the equation y=x26x+5y = x^2 - 6x + 5. To complete the square, we need to find the value that makes x26xx^2 - 6x a perfect square trinomial. We do this by taking half of the coefficient of xx, squaring it, and adding it to and subtracting it from the equation.\newlineHalf of 6-6 is 3-3, and (3)2=9(-3)^2 = 9. So we add and subtract 99 from the right side of the equation.\newliney=x26x+99+5y = x^2 - 6x + 9 - 9 + 5
  3. Rewrite with perfect square: Rewrite the equation with the perfect square trinomial and combine like terms.\newlineNow we have y=(x26x+9)9+5y = (x^2 - 6x + 9) - 9 + 5, which simplifies to y=(x3)24y = (x - 3)^2 - 4.

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