The equation of a parabola is y=x2−6x+5. Write the equation in vertex form.Write any numbers as integers or simplified proper or improper fractions.______
Q. The equation of a parabola is y=x2−6x+5. Write the equation in vertex form.Write any numbers as integers or simplified proper or improper fractions.______
Identify vertex form: Identify the vertex form of a parabola.The vertex form of a parabola is given by y=a(x−h)2+k, where (h,k) is the vertex of the parabola.
Complete the square:Complete the square to transform the given equation into vertex form.We start with the equation y=x2−6x+5. To complete the square, we need to find the value that makes x2−6x a perfect square trinomial. We do this by taking half of the coefficient of x, squaring it, and adding it to and subtracting it from the equation.Half of −6 is −3, and (−3)2=9. So we add and subtract 9 from the right side of the equation.y=x2−6x+9−9+5
Rewrite with perfect square: Rewrite the equation with the perfect square trinomial and combine like terms.Now we have y=(x2−6x+9)−9+5, which simplifies to y=(x−3)2−4.
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