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The equation of a parabola is y=x210x+22y = x^2 - 10x + 22. Write the equation in vertex form.\newlineWrite any numbers as integers or simplified proper or improper fractions.\newline______

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Q. The equation of a parabola is y=x210x+22y = x^2 - 10x + 22. Write the equation in vertex form.\newlineWrite any numbers as integers or simplified proper or improper fractions.\newline______
  1. Identify Vertex Form: Identify the vertex form of a parabola. The vertex form of a parabola is given by y=a(xh)2+ky = a(x - h)^2 + k, where (h,k)(h, k) is the vertex of the parabola.
  2. Complete the Square: Complete the square to rewrite the equation in vertex form.\newlineWe have the equation y=x210x+22y = x^2 - 10x + 22. To complete the square, we need to find the value that makes x210xx^2 - 10x a perfect square trinomial. This value is given by (10/2)2=25(10/2)^2 = 25. We will add and subtract 2525 inside the equation.
  3. Add and Subtract 2525: Add and subtract 2525 to the equation.\newliney=x210x+22y = x^2 - 10x + 22\newliney=x210x+2525+22y = x^2 - 10x + 25 - 25 + 22\newlineNow, we have added 2525 and subtracted 2525, which keeps the equation balanced.
  4. Group and Combine: Group the perfect square trinomial and combine the constants.\newliney=(x210x+25)25+22y = (x^2 - 10x + 25) - 25 + 22\newliney=(x5)23y = (x - 5)^2 - 3\newlineNow, the equation is in vertex form, where (x5)2(x - 5)^2 is the perfect square trinomial and 3-3 is the combination of the constants.

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