The equation of a parabola is y=x2−10x+22. Write the equation in vertex form.Write any numbers as integers or simplified proper or improper fractions.______
Q. The equation of a parabola is y=x2−10x+22. Write the equation in vertex form.Write any numbers as integers or simplified proper or improper fractions.______
Identify Vertex Form: Identify the vertex form of a parabola. The vertex form of a parabola is given by y=a(x−h)2+k, where (h,k) is the vertex of the parabola.
Complete the Square:Complete the square to rewrite the equation in vertex form.We have the equation y=x2−10x+22. To complete the square, we need to find the value that makes x2−10x a perfect square trinomial. This value is given by (10/2)2=25. We will add and subtract 25 inside the equation.
Add and Subtract 25: Add and subtract 25 to the equation.y=x2−10x+22y=x2−10x+25−25+22Now, we have added 25 and subtracted 25, which keeps the equation balanced.
Group and Combine: Group the perfect square trinomial and combine the constants.y=(x2−10x+25)−25+22y=(x−5)2−3Now, the equation is in vertex form, where (x−5)2 is the perfect square trinomial and −3 is the combination of the constants.
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