The equation of a circle is (x+3)^(2)+(y-4)^(2)=49. What are the center and radius of the circle? Choose 1 answer: A The center is (3,4) and the radius is 7 . B The center is (-3,4) and the radius is 7 . (C) The center is (-3,-4) and the radius is 7 . (D) The center is (-3,4) and the radius is 49 .

Rewrite Equation: Rewrite the given equation in standard form to identify the center and radius. Identify Center: Identify the center (h, k) by comparing with the standard form of a circle equation, (x-h)^2 + (y-k)^2 = r^2. Determine Radius: Determine the radius by taking the square root of 49.

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The equation of a circle is $\newline$ $(x+3)^{2}+(y-4)^{2}=49$ . What are the center and radius of the circle? $\newline$ Choose $1$ answer: $\newline$ A The center is $\newline$ $(3,4)$ and the radius is $7$ . $\newline$ B The center is $\newline$ $(-3,4)$ and the radius is $7$ . $\newline$ (C) The center is $\newline$ $(-3,-4)$ and the radius is $7$ . $\newline$ (D) The center is $\newline$ $(-3,4)$ and the radius is $49$ .

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Math Problems

Algebra 2

Find properties of circles from equations in general form

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Q. The equation of a circle is

\newline

(x+3)^{2}+(y-4)^{2}=49

. What are the center and radius of the circle?

\newline

Choose

1

answer:

\newline

A The center is

\newline

(3,4)

and the radius is

7

\newline

B The center is

\newline

(-3,4)

and the radius is

7

\newline

\newline

(-3,-4)

and the radius is

7

\newline

(D) The center is

\newline

(-3,4)

and the radius is

49

Rewrite Equation: Rewrite the given equation in standard form to identify the center and radius.
Identify Center: Identify the center $(h, k)$ by comparing with the standard form of a circle equation, $(x-h)^2 + (y-k)^2 = r^2$ .
Determine Radius: Determine the radius by taking the square root of $49$ .