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Write the equation in standard form for the circle x2+y216=0x^2+y^2-16= 0.

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Q. Write the equation in standard form for the circle x2+y216=0x^2+y^2-16= 0.
  1. Identify equation and goal: Identify the given equation and the goal.\newlineThe given equation is x2+y216=0x^2 + y^2 - 16 = 0. We need to write this equation in the standard form of a circle, which is (xh)2+(yk)2=r2(x - h)^2 + (y - k)^2 = r^2, where (h,k)(h, k) is the center of the circle and rr is the radius.
  2. Move constant term: Move the constant term to the other side of the equation.\newlineTo get the equation in standard form, we need to isolate the terms with xx and yy on one side and move the constant to the other side. We do this by adding 1616 to both sides of the equation.\newlinex2+y216+16=0+16x^2 + y^2 - 16 + 16 = 0 + 16\newlineThis simplifies to:\newlinex2+y2=16x^2 + y^2 = 16
  3. Verify standard form: Verify the standard form of the circle.\newlineThe equation x2+y2=16x^2 + y^2 = 16 is now in the standard form of a circle with a center at (0,0)(0, 0) and a radius of 44, since 1616 is the square of 44.

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