What is the radius of the circle x^2 + y^2 = 36? Simplify any fractions. ____

Given equation: The given equation is x^2 + y^2 = 36. This equation represents a circle centered at the origin (0,0) with a radius r. The general form of a circle's equation is (x - h)^2 + (y - k)^2 = r^2, where (h,k) is the center of the circle and r is the radius. By comparing the given equation with the general form, we can see that h = 0, k = 0, and r^2 = 36.Comparison with general form: To find the radius r, we need to take the square root of r^2. The square root of 36 is 6. Since the radius of a circle is always a positive value, we disregard the negative square root. r = sqrt(36) = 6

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What is the radius of the circle $x^2 + y^2 = 36$ ? $\newline$ Simplify any fractions. $\newline$ ____

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Algebra 2

Find the radius or diameter of a circle

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Q. What is the radius of the circle

x^2 + y^2 = 36

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Simplify any fractions.

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____

Given equation: The given equation is $x^2 + y^2 = 36$ . This equation represents a circle centered at the origin $(0,0)$ with a radius $r$ . The general form of a circle's equation is $(x - h)^2 + (y - k)^2 = r^2$ , where $(h,k)$ is the center of the circle and $r$ is the radius. By comparing the given equation with the general form, we can see that $h = 0$ , $k = 0$ , and $r^2 = 36$ .
Comparison with general form: To find the radius $r$ , we need to take the square root of $r^2$ . The square root of $36$ is $6$ . Since the radius of a circle is always a positive value, we disregard the negative square root. $\newline$ $r = \sqrt{36} = 6$