What is the center of the circle x^2 + y^2 = 144? Simplify any fractions. (____,____)

Equation of a Circle: The equation of a circle in standard form is (x - h)^2 + (y - k)^2 = r^2, where (h, k) is the center of the circle and r is the radius. We need to compare the given equation x^2 + y^2 = 144 with the standard form to find the values of h and k.Rewriting the Given Equation: The given equation x^2 + y^2 = 144 can be rewritten as (x - 0)^2 + (y - 0)^2 = 144 to match the standard form. This implies that h = 0 and k = 0, since there are no values being subtracted from x and y in the given equation.Finding the Center of the Circle: Since we have found that h = 0 and k = 0, the center of the circle described by the equation x^2 + y^2 = 144 is at the point (0, 0).

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What is the center of the circle $x^2 + y^2 = 144$ $?$ $\newline$ Simplify any fractions. $\newline$ (,) $\newline$

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Algebra 2

Find the center of a circle

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Q. What is the center of the circle

x^2 + y^2 = 144

?

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Simplify any fractions.

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Equation of a Circle: The equation of a circle in standard form is $(x - h)^2 + (y - k)^2 = r^2$ , where $(h, k)$ is the center of the circle and $r$ is the radius. We need to compare the given equation $x^2 + y^2 = 144$ with the standard form to find the values of $h$ and $k$ .
Rewriting the Given Equation: The given equation $x^2 + y^2 = 144$ can be rewritten as $(x - 0)^2 + (y - 0)^2 = 144$ to match the standard form. This implies that $h = 0$ and $k = 0$ , since there are no values being subtracted from $x$ and $y$ in the given equation.
Finding the Center of the Circle: Since we have found that $h = 0$ and $k = 0$ , the center of the circle described by the equation $x^2 + y^2 = 144$ is at the point $(0, 0)$ .