Write the equation in standard form for the circle x^2+y^2–4x+7= 0.

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Identify equation and need: Identify the given equation and the need to complete the square for x. The given equation is x^2 + y^2 – 4x + 7 = 0. To get it into standard form, we need to complete the square for the x terms.Group and leave space: Group the x terms and leave a space for completing the square. x^2 - 4x + ( ) + y^2 = -7 We will add a certain number inside the parentheses to complete the square for the x terms.Calculate number to complete: Calculate the number needed to complete the square for the x terms. To complete the square, we take the coefficient of x, which is -4, divide it by 2, and square it. (-4/2)^2 = 4. Add 4 inside the parentheses to complete the square for the x terms.Add number to both sides: Add the same number to both sides of the equation to maintain equality. x^2 - 4x + 4 + y^2 = -7 + 4 Now the equation is balanced.Factor and simplify: Factor the completed square for the x terms and simplify the right side of the equation. (x - 2)^2 + y^2 = -3 This is the equation with the x terms factored.Ensure positive right side: Since the standard form of a circle's equation is (x - h)^2 + (y - k)^2 = r^2, we need to ensure the right side of the equation is positive because the radius squared must be a positive number. However, we have a negative number on the right side, which indicates a math error. A circle cannot have a negative radius squared.

Write the equation in standard form for the circle $x^2+y^2-4x+7= 0$ .

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Write the equation in standard form for the circle x2+y2−4x+7=0x^2+y^2-4x+7= 0x2+y2−4x+7=0.

Write the equation in standard form for the circle $x^2+y^2-4x+7= 0$ .