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The accompanying data set lists full IQ scores for a random sample of subjects with medium lead levels in their blood and another random sample of subjects with high lead levels in their blood. Use a 0.01 significance level to test the claim that IQ scores of subjects with medium lead levels vary more than IQ scores of subjects with high lead levels.




Medium
83
86
92
72
77
91
82
46



98
93
114
79
71
90
111
78













High
101
85
85
82
79
76
104
88



104
94
89
80
75
93
75





Let sample 1 be the sample with the larger sample variance, and let sample 2 be the sample with the smaller sample variance. What are the null and alternative hypotheses?
A. 
H_(0):sigma_(1)^(2)=sigma_(2)^(2)
B.

{:[H_(0):sigma_(1)^(2)=sigma_(2)^(2)],[H_(1):sigma_(1)^(2)!=sigma_(2)^(2)]:}

H_(1):sigma_(1)^(2) < sigma_(2)^(2)
C. 
H_(0):sigma_(1)^(2)=sigma_(2)^(2)

H_(1):sigma_(1)^(2) > sigma_(2)^(2)
D.

{:[H_(0):sigma_(1)^(2)!=sigma_(2)^(2)],[H_(1):sigma_(1)^(2)=sigma_(2)^(2)]:}
Identify the test statistic.
The test statistic is 
◻
(Round to two decimal places as needed.)

The accompanying data set lists full IQ scores for a random sample of subjects with medium lead levels in their blood and another random sample of subjects with high lead levels in their blood. Use a 00.0101 significance level to test the claim that IQ scores of subjects with medium lead levels vary more than IQ scores of subjects with high lead levels.\newline\begin{tabular}{lrrrrrrrr} \newlineMedium & 8383 & 8686 & 9292 & 7272 & 7777 & 9191 & 8282 & 4646 \\\newline& 9898 & 9393 & 114114 & 7979 & 7171 & 9090 & 111111 & 7878 \\\newline& & & & & & & & \\\newlineHigh & 101101 & 8585 & 8585 & 8282 & 7979 & 7676 & 104104 & 8888 \\\newline& 104104 & 9494 & 8989 & 8080 & 7575 & 9393 & 7575 &\newline\end{tabular}\newlineLet sample 11 be the sample with the larger sample variance, and let sample 22 be the sample with the smaller sample variance. What are the null and alternative hypotheses?\newlineA. H0:σ12=σ22 H_{0}: \sigma_{1}^{2}=\sigma_{2}^{2} \newlineB.\newlineH0:σ12=σ22H1:σ12σ22 \begin{array}{l} H_{0}: \sigma_{1}^{2}=\sigma_{2}^{2} \\ H_{1}: \sigma_{1}^{2} \neq \sigma_{2}^{2} \end{array} \newline \mathrm{H}_{1}: \sigma_{1}^{2}<\sigma_{2}^{2} \newlineC. H0:σ12=σ22 \mathrm{H}_{0}: \sigma_{1}^{2}=\sigma_{2}^{2} \newline \mathrm{H}_{1}: \sigma_{1}^{2}>\sigma_{2}^{2} \newlineD.\newlineH0:σ12σ22H1:σ12=σ22 \begin{array}{l} H_{0}: \sigma_{1}^{2} \neq \sigma_{2}^{2} \\ H_{1}: \sigma_{1}^{2}=\sigma_{2}^{2} \end{array} \newlineIdentify the test statistic.\newlineThe test statistic is \square \newline(Round to two decimal places as needed.)

Full solution

Q. The accompanying data set lists full IQ scores for a random sample of subjects with medium lead levels in their blood and another random sample of subjects with high lead levels in their blood. Use a 00.0101 significance level to test the claim that IQ scores of subjects with medium lead levels vary more than IQ scores of subjects with high lead levels.\newline\begin{tabular}{lrrrrrrrr} \newlineMedium & 8383 & 8686 & 9292 & 7272 & 7777 & 9191 & 8282 & 4646 \\\newline& 9898 & 9393 & 114114 & 7979 & 7171 & 9090 & 111111 & 7878 \\\newline& & & & & & & & \\\newlineHigh & 101101 & 8585 & 8585 & 8282 & 7979 & 7676 & 104104 & 8888 \\\newline& 104104 & 9494 & 8989 & 8080 & 7575 & 9393 & 7575 &\newline\end{tabular}\newlineLet sample 11 be the sample with the larger sample variance, and let sample 22 be the sample with the smaller sample variance. What are the null and alternative hypotheses?\newlineA. H0:σ12=σ22 H_{0}: \sigma_{1}^{2}=\sigma_{2}^{2} \newlineB.\newlineH0:σ12=σ22H1:σ12σ22 \begin{array}{l} H_{0}: \sigma_{1}^{2}=\sigma_{2}^{2} \\ H_{1}: \sigma_{1}^{2} \neq \sigma_{2}^{2} \end{array} \newlineH1:σ12<σ22 \mathrm{H}_{1}: \sigma_{1}^{2}<\sigma_{2}^{2} \newlineC. H0:σ12=σ22 \mathrm{H}_{0}: \sigma_{1}^{2}=\sigma_{2}^{2} \newlineH1:σ12>σ22 \mathrm{H}_{1}: \sigma_{1}^{2}>\sigma_{2}^{2} \newlineD.\newlineH0:σ12σ22H1:σ12=σ22 \begin{array}{l} H_{0}: \sigma_{1}^{2} \neq \sigma_{2}^{2} \\ H_{1}: \sigma_{1}^{2}=\sigma_{2}^{2} \end{array} \newlineIdentify the test statistic.\newlineThe test statistic is \square \newline(Round to two decimal places as needed.)
  1. Calculate sample variances: First, calculate the sample variances for both groups. For the medium lead level group: s12=1(n11)Σ(xixˉ1)2s_1^2 = \frac{1}{(n_1-1)} \cdot \Sigma(x_i - \bar{x}_1)^2
  2. Identify larger variance: For the high lead level group: s22=(1n21)Σ(xixˉ2)2s_2^2 = \left(\frac{1}{n_2-1}\right) * \Sigma(x_i - \bar{x}_2)^2
  3. Formulate hypotheses: Now, identify which sample variance is larger to determine sample 11 and sample 22.
  4. Calculate F-test statistic: The null hypothesis H0H_0 assumes that the two variances are equal, and the alternative hypothesis H1H_1 for this test is that the variance of the medium lead level group is greater than the variance of the high lead level group. So, the correct hypotheses are:\newlineH0:σ12=σ22H_0: \sigma_1^2 = \sigma_2^2\newlineH_1: \sigma_1^2 > \sigma_2^2
  5. Calculate F-test statistic: The null hypothesis H0H_0 assumes that the two variances are equal, and the alternative hypothesis H1H_1 for this test is that the variance of the medium lead level group is greater than the variance of the high lead level group. So, the correct hypotheses are:\newlineH0:σ12=σ22H_0: \sigma_1^2 = \sigma_2^2\newlineH_1: \sigma_1^2 > \sigma_2^2 The test statistic for comparing two variances is the F-test statistic, which is calculated as:\newlineF=s12s22F = \frac{s_1^2}{s_2^2}
  6. Calculate F-test statistic: The null hypothesis H0H_0 assumes that the two variances are equal, and the alternative hypothesis H1H_1 for this test is that the variance of the medium lead level group is greater than the variance of the high lead level group. So, the correct hypotheses are:\newlineH0:σ12=σ22H_0: \sigma_1^2 = \sigma_2^2\newlineH_1: \sigma_1^2 > \sigma_2^2 The test statistic for comparing two variances is the F-test statistic, which is calculated as:\newlineF=s12s22F = \frac{s_1^2}{s_2^2} Calculate the F-test statistic using the sample variances obtained earlier. Round to two decimal places.

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