Bytelearn - cat image with glassesAI tutor

Welcome to Bytelearn!

Let’s check out your problem:

Suppose that the functions 
f and 
g are defined as follows.

{:[f(x)=(9)/(2x)","x!=0],[g(x)=5x-4]:}
Find the compositions 
f@f and 
g@g.
Simplify your answers as much as possible.
(Assume that your expressions are defined for all 
x in the dor

{:[(f@f)(x)=◻],[(g@g)(x)=◻]:}

Suppose that the functions f f and g g are defined as follows.\newlinef(x)=92x,x0g(x)=5x4 \begin{array}{l} f(x)=\frac{9}{2 x}, x \neq 0 \\ g(x)=5 x-4 \end{array} \newlineFind the compositions ff f \circ f and gg g \circ g .\newlineSimplify your answers as much as possible.\newline(Assume that your expressions are defined for all x x in the dor\newline(ff)(x)=(gg)(x)= \begin{array}{l} (f \circ f)(x)=\square \\ (g \circ g)(x)=\square \end{array}

Full solution

Q. Suppose that the functions f f and g g are defined as follows.\newlinef(x)=92x,x0g(x)=5x4 \begin{array}{l} f(x)=\frac{9}{2 x}, x \neq 0 \\ g(x)=5 x-4 \end{array} \newlineFind the compositions ff f \circ f and gg g \circ g .\newlineSimplify your answers as much as possible.\newline(Assume that your expressions are defined for all x x in the dor\newline(ff)(x)=(gg)(x)= \begin{array}{l} (f \circ f)(x)=\square \\ (g \circ g)(x)=\square \end{array}
  1. Calculate f@f(x): Calculate f@f(x), which means f(f(x)).\newlineFirst, substitute f(x) into f:\newlinef(x)=92xf(x) = \frac{9}{2x},\newlinef(f(x))=f(92x)f(f(x)) = f\left(\frac{9}{2x}\right).\newlineNow, substitute 92x\frac{9}{2x} for x in f(x):\newlinef(92x)=92(92x)f\left(\frac{9}{2x}\right) = \frac{9}{2*\left(\frac{9}{2x}\right)}.\newlineSimplify the expression:\newline=9182x= \frac{9}{\frac{18}{2x}}\newline=9(2x18)= 9 * \left(\frac{2x}{18}\right)\newline=92x18= \frac{9 * 2x}{18}\newline=x1= \frac{x}{1}\newline=x= x.
  2. Calculate g@g(x)g@g(x): Calculate g@g(x)g@g(x), which means g(g(x))g(g(x)).\newlineFirst, substitute g(x)g(x) into gg:\newlineg(x)=5x4g(x) = 5x - 4,\newlineg(g(x))=g(5x4)g(g(x)) = g(5x - 4).\newlineNow, substitute 5x45x - 4 for xx in g(x)g(x):\newlineg@g(x)g@g(x)00\newlineg@g(x)g@g(x)11\newlineg@g(x)g@g(x)22.

More problems from Compare linear and exponential growth