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Solving systems of linear equations: advanced

{:[x-y=y-4+2(4.5-2x)],[4(x+2y)=-p+7y]:}
In the system of equations, 
p is a constant. For which value of 
p is there exactly one solution 
(x,y) where 
x=-1 ?
Choose 1 answer:
(A) -5
(B) 9
(c) Any real number
D) None of the above

Solving systems of linear equations: advanced\newlinexyamp;=y4+2(4.52x)4(x+2y)amp;=p+7y \begin{aligned} x-y & =y-4+2(4.5-2 x) \\ 4(x+2 y) & =-p+7 y \end{aligned} \newlineIn the system of equations, p p is a constant. For which value of p p is there exactly one solution (x,y) (x, y) where x=1 x=-1 ?\newlineChoose 11 answer:\newline(A) 5-5\newline(B) 99\newline(c) Any real number\newlineD) None of the above

Full solution

Q. Solving systems of linear equations: advanced\newlinexy=y4+2(4.52x)4(x+2y)=p+7y \begin{aligned} x-y & =y-4+2(4.5-2 x) \\ 4(x+2 y) & =-p+7 y \end{aligned} \newlineIn the system of equations, p p is a constant. For which value of p p is there exactly one solution (x,y) (x, y) where x=1 x=-1 ?\newlineChoose 11 answer:\newline(A) 5-5\newline(B) 99\newline(c) Any real number\newlineD) None of the above
  1. Substitute x = 1-1: Substitute x=1 x = -1 into the first equation.\newlinexy=y4+2(4.52x) x - y = y - 4 + 2(4.5 - 2x) \newline1y=y4+2(4.52(1)) -1 - y = y - 4 + 2(4.5 - 2(-1))
  2. Simplify the equation: \newlineStep 22: Simplify the equation.\newline1y=y4+2(4.5+2) -1 - y = y - 4 + 2(4.5 + 2) \newline1y=y4+2(6.5) -1 - y = y - 4 + 2(6.5) \newline1y=y4+13 -1 - y = y - 4 + 13 \newline1y=y+9 -1 - y = y + 9
  3. Solve for y: \newlineStep 33: Solve for y y .\newline1y=y+9 -1 - y = y + 9 \newline19=y+y -1 - 9 = y + y \newline10=2y -10 = 2y \newliney=5 y = -5
  4. Substitute x = 1-1 and y = 5-5: \newlineStep 44: Substitute x=1 x = -1 and y=5 y = -5 into the second equation.\newline4(x+2y)=p+7y 4(x + 2y) = -p + 7y \newline4(1+2(5))=p+7(5) 4(-1 + 2(-5)) = -p + 7(-5) \newline4(110)=p35 4(-1 - 10) = -p - 35 \newline4(11)=p35 4(-11) = -p - 35 \newline44=p35 -44 = -p - 35
  5. Solve for p: \newlineStep 55: Solve for p p .\newline44+35=p -44 + 35 = -p \newline9=p -9 = -p \newlinep=9 p = 9

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