Solving systems of linear equations: advancedx−y4(x+2y)amp;=y−4+2(4.5−2x)amp;=−p+7yIn the system of equations, p is a constant. For which value of p is there exactly one solution (x,y) where x=−1 ?Choose 1 answer:(A) −5(B) 9(c) Any real numberD) None of the above
Q. Solving systems of linear equations: advancedx−y4(x+2y)=y−4+2(4.5−2x)=−p+7yIn the system of equations, p is a constant. For which value of p is there exactly one solution (x,y) where x=−1 ?Choose 1 answer:(A) −5(B) 9(c) Any real numberD) None of the above
Substitute x = −1: Substitute x=−1 into the first equation.x−y=y−4+2(4.5−2x)−1−y=y−4+2(4.5−2(−1))
Simplify the equation:Step 2: Simplify the equation.−1−y=y−4+2(4.5+2)−1−y=y−4+2(6.5)−1−y=y−4+13−1−y=y+9
Solve for y:Step 3: Solve for y.−1−y=y+9−1−9=y+y−10=2yy=−5
Substitute x = −1 and y = −5:Step 4: Substitute x=−1 and y=−5 into the second equation.4(x+2y)=−p+7y4(−1+2(−5))=−p+7(−5)4(−1−10)=−p−354(−11)=−p−35−44=−p−35
Solve for p:Step 5: Solve for p.−44+35=−p−9=−pp=9
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