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Solve using the quadratic formula.\newline9p2+4p1=09p^2 + 4p - 1 = 0\newlineWrite your answers as integers, proper or improper fractions in simplest form, or decimals rounded to the nearest hundredth.\newlinep=p = _____ or p=p = _____

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Q. Solve using the quadratic formula.\newline9p2+4p1=09p^2 + 4p - 1 = 0\newlineWrite your answers as integers, proper or improper fractions in simplest form, or decimals rounded to the nearest hundredth.\newlinep=p = _____ or p=p = _____
  1. Identify coefficients: Identify the coefficients aa, bb, and cc in the quadratic equation 9p2+4p1=09p^2 + 4p - 1 = 0.a=9a = 9, b=4b = 4, c=1c = -1
  2. Write quadratic formula: Write down the quadratic formula: p=b±b24ac2ap = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}.
  3. Substitute values: Substitute the values of aa, bb, and cc into the quadratic formula.p=(4)±(4)24(9)(1)2(9)p = \frac{{-(4) \pm \sqrt{{(4)^2 - 4\cdot(9)\cdot(-1)}}}}{{2\cdot(9)}}
  4. Simplify square root: Simplify the expression under the square root (b24ac\sqrt{b^2 - 4ac}).\newline(4)24(9)(1)=16+36=52\sqrt{(4)^2 - 4\cdot(9)\cdot(-1)} = \sqrt{16 + 36} = \sqrt{52}
  5. Simplify formula: Simplify the quadratic formula with the values. p=4±5218p = \frac{{-4 \pm \sqrt{52}}}{{18}}
  6. Calculate solutions: Calculate the two possible solutions for pp.p=4+5218p = \frac{{-4 + \sqrt{52}}}{{18}} or p=45218p = \frac{{-4 - \sqrt{52}}}{{18}}
  7. Round values: Round the values of pp to the nearest hundredth, if necessary.p(4+7.21)/18p \approx (-4 + 7.21) / 18 or p(47.21)/18p \approx (-4 - 7.21) / 18p3.21/18p \approx 3.21 / 18 or p11.21/18p \approx -11.21 / 18p0.18p \approx 0.18 or p0.62p \approx -0.62

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