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Solve using the quadratic formula.\newline4k2k8=04k^2 - k - 8 = 0\newlineWrite your answers as integers, proper or improper fractions in simplest form, or decimals rounded to the nearest hundredth.\newlinek=k = _____ or k=k = _____

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Q. Solve using the quadratic formula.\newline4k2k8=04k^2 - k - 8 = 0\newlineWrite your answers as integers, proper or improper fractions in simplest form, or decimals rounded to the nearest hundredth.\newlinek=k = _____ or k=k = _____
  1. Identify coefficients: Identify the coefficients aa, bb, and cc in the quadratic equation 4k2k8=04k^2 − k − 8 = 0 by comparing it to the standard form ax2+bx+c=0ax^2 + bx + c = 0.\newlinea=4a = 4, b=1b = -1, c=8c = -8
  2. Substitute values into formula: Substitute the values of aa, bb, and cc into the quadratic formula, k=b±b24ac2ak = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}.k=(1)±(1)244(8)24k = \frac{-(-1) \pm \sqrt{(-1)^2 - 4\cdot4\cdot(-8)}}{2\cdot4}
  3. Simplify expression and constants: Simplify the expression inside the square root and the constants outside the square root. \newlinek=1±1+1288k = \frac{1 \pm \sqrt{1 + 128}}{8}\newlinek=1±1298k = \frac{1 \pm \sqrt{129}}{8}
  4. Calculate square root of 129129: Calculate the square root of 129129 to find the two possible solutions for kk.12911.36\sqrt{129} \approx 11.36 (rounded to two decimal places)k=1+11.368k = \frac{1 + 11.36}{8} or k=111.368k = \frac{1 - 11.36}{8}
  5. Solve for two values of kk: Solve for the two values of kk.k(1+11.36)/8k \approx (1 + 11.36) / 8 or k(111.36)/8k \approx (1 - 11.36) / 8k12.36/8k \approx 12.36 / 8 or k10.36/8k \approx -10.36 / 8k1.55k \approx 1.55 or k1.295k \approx -1.295

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