Solve using the quadratic formula. 2y^2 − 5y − 2 = 0 Write your answers as integers, proper or improper fractions in simplest form, or decimals rounded to the nearest hundredth. y = _____ or y = _____

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Solve using the quadratic formula.  2y^2 − 5y − 2 = 0 Write your answers as integers, proper or improper fractions in simplest form, or decimals rounded to the nearest hundredth.  y = _____ or y = _____

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Identify values: Identify the values of a, b, and c in the quadratic equation 2y^2 − 5y − 2 = 0. The quadratic equation is in the form ay^2 + by + c = 0. Comparing this with our equation, we get: a = 2 b = -5 c = -2Substitute formula: Substitute the values of a, b, and c into the quadratic formula y = (-b ± sqrt(b^2 - 4ac)) / (2a). Substitute a = 2, b = -5, and c = -2 into the formula. y = (-(-5) ± sqrt((-5)^2 - 4*2*(-2))) / (2*2) y = (5 ± sqrt(25 + 16)) / 4Simplify and solve: Simplify the expression under the square root and solve for y. y = (5 ± sqrt(25 + 16)) / 4 y = (5 ± sqrt(41)) / 4 Now we have two possible solutions for y: y = (5 + sqrt(41)) / 4 or y = (5 - sqrt(41)) / 4Calculate numerical values: Calculate the numerical values of y to the nearest hundredth, if necessary. First solution: y = (5 + sqrt(41)) / 4 y ≈ (5 + 6.40) / 4 y ≈ 11.40 / 4 y ≈ 2.85  Second solution: y = (5 - sqrt(41)) / 4 y ≈ (5 - 6.40) / 4 y ≈ -1.40 / 4 y ≈ -0.35

Solve using the quadratic formula. $\newline$ $2y^2 - 5y - 2 = 0$ $\newline$ Write your answers as integers, proper or improper fractions in simplest form, or decimals rounded to the nearest hundredth. $\newline$ $y =$ _ or $y =$ _

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Solve using the quadratic formula.\newline2y2−5y−2=02y^2 - 5y - 2 = 02y2−5y−2=0\newlineWrite your answers as integers, proper or improper fractions in simplest form, or decimals rounded to the nearest hundredth.\newliney=y = y=_____ or y=y = y=_____

Solve using the quadratic formula. $\newline$ $2y^2 - 5y - 2 = 0$ $\newline$ Write your answers as integers, proper or improper fractions in simplest form, or decimals rounded to the nearest hundredth. $\newline$ $y =$ _ or $y =$ _