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Solve the inequality and graph the solution. 2(h+8)<8

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−10x−3≥8x+4 -10 x-3 \geq 8 x+4 \newlineWhich of the following best describes the solutions to the inequality shown?\newlineChoose 11 answer:\newlineA) x≤−718 x \leq-\frac{7}{18} \newline(B) x≤−72 x \leq-\frac{7}{2} \newline(C) x≤−118 x \leq-\frac{1}{18} \newline(D) x≥−718 x \geq-\frac{7}{18}
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−12x<−72 -12 x<-72 \newlineWhich of the following best describes the solutions to the inequality shown?\newlineChoose 11 answer:\newline(A) x<6 x<6 \newline(B) x>6 x>6 \newline(C) x<16 x<\frac{1}{6} \newline(D) x>16 x>\frac{1}{6}
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8x+6<4x+10 8 x+6<4 x+10 \newlineWhich of the following best describes the solutions to the inequality shown?\newlineChoose 11 answer:\newline(A) x<13 x<\frac{1}{3} \newline(B) x<4 x<4 \newline(C) x<1 x<1 \newline(D) x>1 x>1
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6x−2<2x+3 6 x-2<2 x+3 \newlineWhich of the following best describes the solutions to the inequality shown?\newlineChoose 11 answer:\newline(A) x<54 x<\frac{5}{4} \newline(B) x>54 x>\frac{5}{4} \newline(C) x<14 x<\frac{1}{4} \newline(D) x<58 x<\frac{5}{8}
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16<−4x 16<-4 x \newlineWhich of the following best describes the solutions to the inequality shown?\newlineChoose 11 answer:\newline(A) x<−4 x<-4 \newline(B) x>−4 x>-4 \newline(C) x<−14 x<-\frac{1}{4} \newline(D) x>−14 x>-\frac{1}{4}
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Find lim⁡x→42−4x−12x−4 \lim _{x \rightarrow 4} \frac{2-\sqrt{4 x-12}}{x-4} .\newlineChoose 11 answer:\newline(A) 22\newline(B) 11\newline(C) −1-1\newline(D) The limit doesn't exist
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Posted 9 months ago

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Find lim⁡x→2x4−4x3+4x2x−2 \lim _{x \rightarrow 2} \frac{x^{4}-4 x^{3}+4 x^{2}}{x-2} .\newlineChoose 11 answer:\newline(A) −4-4\newline(B) 00\newline(C) 44\newline(D) The limit doesn't exist
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Posted 9 months ago

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Let f f be a continuous function on the closed interval [−5,0] [-5,0] , where f(−5)=0 f(-5)=0 and f(0)=5 f(0)=5 .\newlineWhich of the following is guaranteed by the Intermediate Value Theorem?\newlineChoose 11 answer:\newline(A) f(c)=−2 f(c)=-2 for at least one c c between 00 and 55\newline(B) f(c)=2 f(c)=2 for at least one c c between 00 and 55\newline(C) f(c)=−2 f(c)=-2 for at least one c c between −5-5 and 00\newline(D) f(c)=2 f(c)=2 for at least one c c between −5-5 and 00
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Let g(x)=tan⁡(x) g(x)=\tan (x) .\newlineCan we use the intermediate value theorem to say the equation g(x)=0 g(x)=0 has a solution where π4≤x≤3π4 \frac{\pi}{4} \leq x \leq \frac{3 \pi}{4} ?\newlineChoose 11 answer:\newline(A) No, since the function is not continuous on that interval.\newline(B) No, since 00 is not between g(π4) g\left(\frac{\pi}{4}\right) and g(3π4) g\left(\frac{3 \pi}{4}\right) .\newline(C) Yes, both conditions for using the intermediate value theorem have been met.
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Let g(x)=cos⁡(x) g(x)=\cos (x) .\newlineCan we use the intermediate value theorem to say the equation g(x)=0.8 g(x)=0.8 has a solution where 0≤x≤π2 0 \leq x \leq \frac{\pi}{2} ?\newlineChoose 11 answer:\newline(A) No, since the function is not continuous on that interval.\newline(B) No, since 00.88 is not between g(0) g(0) and g(π2) g\left(\frac{\pi}{2}\right) .\newline(C) Yes, both conditions for using the intermediate value theorem have been met.
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