Q. Solve the equation 2x2+15x+35=x2 to the nearest tenth.Answer: x=
Move Terms, Set Equal: First, we need to move all terms to one side of the equation to set it equal to zero. We will subtract x2 from both sides of the equation.2x2+15x+35−x2=x2−x2This simplifies to:x2+15x+35=0
Factor Quadratic Equation: Next, we need to factor the quadratic equation if possible. We look for two numbers that multiply to 35 and add up to 15. The numbers 5 and 7 fit this requirement.(x+5)(x+7)=0
Apply Zero Product Property: Now, we apply the zero product property which states that if a product of two factors is zero, then at least one of the factors must be zero.So, we set each factor equal to zero:x+5=0 or x+7=0
Solve for x: We solve each equation for x:For x+5=0, we subtract 5 from both sides:x=−5For x+7=0, we subtract 7 from both sides:x=−7These are the two solutions to the equation.
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