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Welcome to Bytelearn!
Let’s check out your problem:
Solve for
x
x
x
and write your answer in simplest form.
\newline
−
9
x
=
−
4
x
+
5
(
−
3
5
x
+
4
5
)
−
8
-9 x=-4 x+5\left(-\frac{3}{5} x+\frac{4}{5}\right)-8
−
9
x
=
−
4
x
+
5
(
−
5
3
x
+
5
4
)
−
8
\newline
Answer:
x
=
x=
x
=
View step-by-step help
Home
Math Problems
Precalculus
Operations with rational exponents
Full solution
Q.
Solve for
x
x
x
and write your answer in simplest form.
\newline
−
9
x
=
−
4
x
+
5
(
−
3
5
x
+
4
5
)
−
8
-9 x=-4 x+5\left(-\frac{3}{5} x+\frac{4}{5}\right)-8
−
9
x
=
−
4
x
+
5
(
−
5
3
x
+
5
4
)
−
8
\newline
Answer:
x
=
x=
x
=
Distribute and Simplify:
First, distribute the
5
5
5
into the parentheses on the right side of the equation.
−
9
x
=
−
4
x
+
5
×
(
−
3
5
)
x
+
5
×
(
4
5
)
−
8
-9x = -4x + 5 \times \left(-\frac{3}{5}\right)x + 5 \times \left(\frac{4}{5}\right) - 8
−
9
x
=
−
4
x
+
5
×
(
−
5
3
)
x
+
5
×
(
5
4
)
−
8
Combine Like Terms:
Simplify the terms inside the equation by multiplying
5
5
5
with each term inside the parentheses.
−
9
x
=
−
4
x
−
3
x
+
4
−
8
-9x = -4x - 3x + 4 - 8
−
9
x
=
−
4
x
−
3
x
+
4
−
8
Add and Subtract:
Combine like terms on the right side of the equation.
\newline
−
9
x
=
−
4
x
−
3
x
−
4
-9x = -4x - 3x - 4
−
9
x
=
−
4
x
−
3
x
−
4
Isolate
x
x
x
Term:
Further simplify the right side by adding the
x
x
x
terms together.
−
9
x
=
−
7
x
−
4
-9x = -7x - 4
−
9
x
=
−
7
x
−
4
Divide and Solve:
Add
7
x
7x
7
x
to both sides of the equation to isolate the
x
x
x
term on one side.
\newline
−
9
x
+
7
x
=
−
7
x
+
7
x
−
4
-9x + 7x = -7x + 7x - 4
−
9
x
+
7
x
=
−
7
x
+
7
x
−
4
\newline
−
2
x
=
−
4
-2x = -4
−
2
x
=
−
4
Final Solution:
Divide both sides of the equation by
−
2
-2
−
2
to solve for
x
x
x
.
x
=
−
4
−
2
x = \frac{-4}{-2}
x
=
−
2
−
4
Final Solution:
Divide both sides of the equation by
−
2
-2
−
2
to solve for
x
x
x
.
x
=
−
4
−
2
x = \frac{-4}{-2}
x
=
−
2
−
4
Simplify the division to find the value of
x
x
x
.
x
=
2
x = 2
x
=
2
More problems from Operations with rational exponents
Question
f
(
x
)
=
6
x
+
5
2
−
14
+
5
x
f(x)=\frac{6 x+5}{2-\sqrt{14+5 x}}
f
(
x
)
=
2
−
14
+
5
x
6
x
+
5
\newline
We want to find
lim
x
→
−
2
f
(
x
)
\lim _{x \rightarrow-2} f(x)
lim
x
→
−
2
f
(
x
)
.
\newline
What happens when we use direct substitution?
\newline
Choose
1
1
1
answer:
\newline
(A) The limit exists, and we found it!
\newline
(B) The limit doesn't exist (probably an asymptote).
\newline
(C) The result is indeterminate.
Get tutor help
Posted 1 year ago
Question
Let
x
4
+
y
2
=
17
x^{4}+y^{2}=17
x
4
+
y
2
=
17
.
\newline
What is the value of
d
2
y
d
x
2
\frac{d^{2} y}{d x^{2}}
d
x
2
d
2
y
at the point
(
−
2
,
1
)
(-2,1)
(
−
2
,
1
)
?
\newline
Give an exact number.
Get tutor help
Posted 1 year ago
Question
What is the area of the region bound by the graphs of
f
(
x
)
=
x
−
2
,
g
(
x
)
=
14
−
x
f(x)=\sqrt{x-2}, g(x)=14-x
f
(
x
)
=
x
−
2
,
g
(
x
)
=
14
−
x
, and
x
=
2
x=2
x
=
2
?
\newline
Choose
1
1
1
answer:
\newline
(A)
19
6
\frac{19}{6}
6
19
\newline
(B)
99
2
\frac{99}{2}
2
99
\newline
(C)
151
2
\frac{151}{2}
2
151
\newline
(D)
45
2
\frac{45}{2}
2
45
Get tutor help
Posted 1 year ago
Question
Let
g
(
x
)
=
x
4
3
g(x)=x^{\frac{4}{3}}
g
(
x
)
=
x
3
4
.
\newline
g
′
(
27
)
=
g^{\prime}(27)=
g
′
(
27
)
=
Get tutor help
Posted 1 year ago
Question
Simplify
ln
(
1
e
)
\ln \left(\frac{1}{\sqrt{e}}\right)
ln
(
e
1
)
\newline
Answer:
Get tutor help
Posted 1 year ago
Question
Simplify
ln
(
1
e
)
\ln \left(\frac{1}{e}\right)
ln
(
e
1
)
\newline
Answer:
Get tutor help
Posted 1 year ago
Question
y
=
(
sin
−
1
(
5
x
2
)
)
3
y=(\sin^{-1}(5x^{2}))^{3}
y
=
(
sin
−
1
(
5
x
2
)
)
3
Get tutor help
Posted 1 year ago
Question
(
10
x
3
−
5
x
2
−
6
x
)
÷
(
2
x
2
)
\left(10x^{3}-5x^{2}-6x\right)\div\left(2x^{2}\right)
(
10
x
3
−
5
x
2
−
6
x
)
÷
(
2
x
2
)
Get tutor help
Posted 1 year ago
Question
y
=
cos
4
x
sin
4
x
y=\cos^{4}x\sin^{4}x
y
=
cos
4
x
sin
4
x
Get tutor help
Posted 1 year ago
Question
3
5
−
3
10
\frac{3}{5}-\frac{3}{10}
5
3
−
10
3
Get tutor help
Posted 1 year ago
Related topics
Algebra - Order of Operations
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`X` and `Y` Axes
Geometry - Scalene Triangle
Common Multiple
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