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Let’s check out your problem:
Solve for
x
\mathrm{x}
x
.
\newline
−
3
2
=
30
x
-\frac{3}{2}=\frac{30}{x}
−
2
3
=
x
30
\newline
Answer:
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Home
Math Problems
Precalculus
Evaluate rational exponents
Full solution
Q.
Solve for
x
\mathrm{x}
x
.
\newline
−
3
2
=
30
x
-\frac{3}{2}=\frac{30}{x}
−
2
3
=
x
30
\newline
Answer:
Identify Equation:
Identify the equation to solve for
x
x
x
. We have the equation
−
3
2
=
30
x
-\frac{3}{2}=\frac{30}{x}
−
2
3
=
x
30
. We need to find the value of
x
x
x
that satisfies this equation.
Cross-Multiply:
Cross-multiply to solve for
x
x
x
. Cross-multiplication gives us
−
3
x
=
2
×
30
-3x = 2 \times 30
−
3
x
=
2
×
30
.
Simplify Equation:
Simplify the right side of the equation.
2
×
30
2 \times 30
2
×
30
equals
60
60
60
, so the equation becomes
−
3
x
=
60
-3x = 60
−
3
x
=
60
.
Divide for x:
Divide both sides by
−
3
-3
−
3
to solve for
x
x
x
. Dividing both sides by
−
3
-3
−
3
gives us
x
=
60
−
3
x = \frac{60}{-3}
x
=
−
3
60
.
Calculate
x
x
x
:
Calculate the value of
x
x
x
.
60
−
3
=
−
20
\frac{60}{-3} = -20
−
3
60
=
−
20
, so
x
=
−
20
x = -20
x
=
−
20
.
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(A) The limit exists, and we found it!
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\newline
(C) The result is indeterminate.
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