Solve for x. -(2)/(3)=(10 )/(x) Answer:

Identify Equation: Identify the equation to solve for x. We have the equation -(2/3) = (10/x). We need to find the value of x that makes this equation true.Cross-Multiply: Cross-multiply to solve for x. Cross-multiplication gives us: -2 * x = 3 * 10Perform Multiplication: Perform the multiplication on the right side of the equation. 3 * 10 = 30 So, -2 * x = 30Divide for x: Divide both sides of the equation by -2 to solve for x. x = 30 / (-2)Calculate x: Calculate the value of x. x = -15

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Solve for
x.

-(2)/(3)=(10 )/(x)
Answer:

Solve for $\mathrm{x}$ . $\newline$ $-\frac{2}{3}=\frac{10}{x}$ $\newline$ Answer:

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Precalculus

Evaluate rational exponents

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Q. Solve for

\mathrm{x}

\newline

-\frac{2}{3}=\frac{10}{x}

\newline

Answer:

Identify Equation: Identify the equation to solve for $x$ . We have the equation $-\left(\frac{2}{3}\right) = \frac{10}{x}$ . We need to find the value of $x$ that makes this equation true.
Cross-Multiply: Cross-multiply to solve for $x$ . Cross-multiplication gives us: $-2 \times x = 3 \times 10$
Perform Multiplication: Perform the multiplication on the right side of the equation. $\newline$ $3 \times 10 = 30$ $\newline$ So, $-2 \times x = 30$
Divide for x: Divide both sides of the equation by $-2$ to solve for $x$ . $x = \frac{30}{(-2)}$
Calculate $x$ : Calculate the value of $x$ . $x = -15$