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Solve by completing the square.\newlines2+24s=47s^2 + 24s = -47\newlineWrite your answers as integers, proper or improper fractions in simplest form, or decimals rounded to the nearest hundredth.\newlines=s = _____ or s=s = _____

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Q. Solve by completing the square.\newlines2+24s=47s^2 + 24s = -47\newlineWrite your answers as integers, proper or improper fractions in simplest form, or decimals rounded to the nearest hundredth.\newlines=s = _____ or s=s = _____
  1. Write equation in form: Write the equation in the form of s2+bs=cs^2 + bs = c. The given equation is already in this form: s2+24s=47s^2 + 24s = -47.
  2. Move constant term: Move the constant term to the right side of the equation.\newlineAdd 4747 to both sides to isolate the s2s^2 and ss terms on the left side.\newlines2+24s+47=0+47s^2 + 24s + 47 = 0 + 47\newlines2+24s=47s^2 + 24s = 47
  3. Find completing square number: Find the number to complete the square.\newlineTake half of the coefficient of ss, square it, and add it to both sides of the equation.\newline(24/2)2=122=144(24/2)^2 = 12^2 = 144\newlines2+24s+144=47+144s^2 + 24s + 144 = 47 + 144\newlines2+24s+144=191s^2 + 24s + 144 = 191
  4. Factor left side: Factor the left side of the equation.\newlineThe left side is now a perfect square trinomial.\newline(s+12)2=191(s + 12)^2 = 191
  5. Take square root: Take the square root of both sides of the equation.\newline(s+12)2=±191\sqrt{(s + 12)^2} = \pm\sqrt{191}\newlines+12=±191s + 12 = \pm\sqrt{191}
  6. Solve for ss: Solve for ss.\newlineSubtract 1212 from both sides to isolate ss.\newlines=12±191s = -12 \pm \sqrt{191}
  7. Calculate approximate decimal values: Calculate the approximate decimal values of ss.19113.82\sqrt{191} \approx 13.82 (rounded to the nearest hundredth)s12+13.82s \approx -12 + 13.82 or s1213.82s \approx -12 - 13.82s1.82s \approx 1.82 or s25.82s \approx -25.82

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