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Solve by completing the square.\newlinej218j=23j^2 - 18j = 23\newlineWrite your answers as integers, proper or improper fractions in simplest form, or decimals rounded to the nearest hundredth.\newlinej=j = _____ or j=j = _____

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Q. Solve by completing the square.\newlinej218j=23j^2 - 18j = 23\newlineWrite your answers as integers, proper or improper fractions in simplest form, or decimals rounded to the nearest hundredth.\newlinej=j = _____ or j=j = _____
  1. Move Constant Term: Rewrite the equation in the form of j2+bj=cj^2 + bj = c. We have the equation j218j=23j^2 - 18j = 23. To complete the square, we need to move the constant term to the other side of the equation. j218j+___=23+___j^2 - 18j + \_\_\_ = 23 + \_\_\_
  2. Find Completing Number: Find the number to complete the square.\newlineTo complete the square, we need to add (b/2)2(b/2)^2 to both sides of the equation, where bb is the coefficient of jj. In this case, b=18b = -18.\newline(18/2)2=81(-18/2)^2 = 81\newlineSo we add 8181 to both sides of the equation.\newlinej218j+81=23+81j^2 − 18j + 81 = 23 + 81
  3. Factor and Simplify: Factor the left side of the equation and simplify the right side.\newlineThe left side of the equation is now a perfect square trinomial.\newline(j9)2=104(j - 9)^2 = 104
  4. Take Square Root: Take the square root of both sides of the equation.\newlineTo solve for jj, we take the square root of both sides.\newline(j9)2=±104\sqrt{(j − 9)^2} = \pm\sqrt{104}\newlinej9=±104j − 9 = \pm\sqrt{104}
  5. Solve for j: Solve for j.\newlineWe add 99 to both sides of the equation to isolate jj.\newlinej=9±104j = 9 \pm \sqrt{104}\newlineSince 104\sqrt{104} is approximately 10.2010.20, we can write the approximate solutions.\newlinej9+10.20j \approx 9 + 10.20 or j910.20j \approx 9 - 10.20\newlinej19.20j \approx 19.20 or j1.20j \approx -1.20

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