simplest form. (1)/(48)+(5)/(6)

Identify LCM: Identify the least common multiple (LCM) of the denominators 48 and 6 to combine the fractions. The LCM of 48 and 6 is 48 because 48 is the smallest number that both 6 and 48 can divide into without leaving a remainder.Convert Fraction: Convert the fraction 5/6 to have the common denominator of 48. To do this, multiply both the numerator and the denominator by 8, because 48 divided by 6 equals 8. 5/6 * 8/8 = 40/48Add Numerators: Now that both fractions have the same denominator, add the numerators together. 1/48 + 40/48 = (1 + 40)/48Perform Addition: Perform the addition of the numerators. 1 + 40 = 41 So, 1/48 + 40/48 = 41/48Simplify Fraction: The fraction 41/48 is already in its simplest form because 41 and 48 have no common factors other than 1.

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Find the sum.Give your answer in simplest form. $\newline$ $\frac{1}{48}+\frac{5}{6}$

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Q. Find the sum.Give your answer in simplest form.

\newline

\frac{1}{48}+\frac{5}{6}

Identify LCM: Identify the least common multiple (LCM) of the denominators $48$ and $6$ to combine the fractions. $\newline$ The LCM of $48$ and $6$ is $48$ because $48$ is the smallest number that both $6$ and $48$ can divide into without leaving a remainder.
Convert Fraction: Convert the fraction $\frac{5}{6}$ to have the common denominator of $48$ . To do this, multiply both the numerator and the denominator by $8$ , because $48$ divided by $6$ equals $8$ . $\frac{5}{6} \times \frac{8}{8} = \frac{40}{48}$
Add Numerators: Now that both fractions have the same denominator, add the numerators together. $\frac{1}{48} + \frac{40}{48} = \frac{(1 + 40)}{48}$
Perform Addition: Perform the addition of the numerators. $1 + 40 = 41$ So, $\frac{1}{48} + \frac{40}{48} = \frac{41}{48}$
Simplify Fraction: The fraction $\frac{41}{48}$ is already in its simplest form because $41$ and $48$ have no common factors other than $1$ .