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Select the answer which is equivalent to the given expression using your calculator.

sin(arccos ((5)/(sqrt250)))

(5)/(15)

(5)/(sqrt250)

(15)/(5)

(15)/(sqrt250)

Select the answer which is equivalent to the given expression using your calculator.\newlinesin(arccos5250) \sin \left(\arccos \frac{5}{\sqrt{250}}\right) \newline515 \frac{5}{15} \newline5250 \frac{5}{\sqrt{250}} \newline155 \frac{15}{5} \newline15250 \frac{15}{\sqrt{250}}

Full solution

Q. Select the answer which is equivalent to the given expression using your calculator.\newlinesin(arccos5250) \sin \left(\arccos \frac{5}{\sqrt{250}}\right) \newline515 \frac{5}{15} \newline5250 \frac{5}{\sqrt{250}} \newline155 \frac{15}{5} \newline15250 \frac{15}{\sqrt{250}}
  1. Understand Relationship Sine Cosine: Understand the relationship between sine and cosine in a right triangle.\newlineThe sine of an angle is equal to the opposite side over the hypotenuse, and the cosine of an angle is equal to the adjacent side over the hypotenuse. In a right triangle, sin(θ)=oppositehypotenuse\sin(\theta) = \frac{\text{opposite}}{\text{hypotenuse}} and cos(θ)=adjacenthypotenuse\cos(\theta) = \frac{\text{adjacent}}{\text{hypotenuse}}. Since arccos\text{arccos} gives us an angle whose cosine is the provided value, we can use this relationship to find the sine of that angle.
  2. Evaluate Expression Inside Arccos: Evaluate the expression inside the arccos function.\newlineWe have arccos(5250)\arccos\left(\frac{5}{\sqrt{250}}\right). First, simplify 250\sqrt{250} to 5105\sqrt{10} to make calculations easier.
  3. Recognize Simplifies Arccos: Recognize that arccos(5510)\arccos\left(\frac{5}{5\sqrt{10}}\right) simplifies to arccos(110)\arccos\left(\frac{1}{\sqrt{10}}\right). This means we are looking for an angle whose cosine is 110\frac{1}{\sqrt{10}}. In a right triangle, this would correspond to the adjacent side being 11 and the hypotenuse being 10\sqrt{10}.
  4. Use Pythagorean Theorem: Use the Pythagorean theorem to find the length of the opposite side.\newlineIn a right triangle with hypotenuse 10\sqrt{10} and adjacent side 11, the opposite side can be found using the Pythagorean theorem: opposite2+adjacent2=hypotenuse2\text{opposite}^2 + \text{adjacent}^2 = \text{hypotenuse}^2. Plugging in the values, we get opposite2+12=(10)2\text{opposite}^2 + 1^2 = (\sqrt{10})^2.
  5. Solve for Opposite Side: Solve for the opposite side.\newlineCalculating the above equation gives us opposite2+1=10\text{opposite}^2 + 1 = 10. Subtracting 11 from both sides, we get opposite2=9\text{opposite}^2 = 9. Taking the square root of both sides, we find that the opposite side is 33.
  6. Calculate Sin Arccos: Calculate sin(arccos(5250))\sin(\arccos(\frac{5}{\sqrt{250}})) using the opposite side and the hypotenuse.\newlineNow that we know the opposite side is 33 and the hypotenuse is 10\sqrt{10}, we can find the sine of the angle: sin(arccos(5250))=oppositehypotenuse=310\sin(\arccos(\frac{5}{\sqrt{250}})) = \frac{\text{opposite}}{\text{hypotenuse}} = \frac{3}{\sqrt{10}}.
  7. Rationalize Denominator Fraction: Rationalize the denominator of the fraction.\newlineTo rationalize the denominator, multiply the numerator and the denominator by 10\sqrt{10}: 310\frac{3}{\sqrt{10}} * 1010\frac{\sqrt{10}}{\sqrt{10}} = 31010\frac{3\sqrt{10}}{10}.
  8. Simplify Expression: Simplify the expression.\newlineSimplifying the expression gives us (310)/(10)=(310)/(25)=(310)/(21010)=3/(210)(3\sqrt{10})/(10) = (3\sqrt{10})/(2\cdot 5) = (3\sqrt{10})/(2\sqrt{10}\cdot\sqrt{10}) = 3/(2\sqrt{10}).
  9. Compare with Answer Choices: Compare the simplified expression with the answer choices.\newlineThe expression 3210\frac{3}{2\sqrt{10}} does not match any of the provided answer choices exactly. However, we can simplify further by dividing both the numerator and the denominator by the common factor of 33: 3210=12103=12310=12310=3210\frac{3}{2\sqrt{10}} = \frac{1}{\frac{2\sqrt{10}}{3}} = \frac{1}{\frac{2}{3}\sqrt{10}} = \frac{1}{\frac{2}{3}\sqrt{10}} = \frac{3}{2\sqrt{10}}.
  10. Realize Mistake and Correct: Realize a mistake was made in the previous step and correct it.\newlineThe correct simplification should be (3)/(210)=(3/3)/(210/3)=(1)/(210/3)=(3)/(210)(3)/(2\sqrt{10}) = (3/3)/(2\sqrt{10}/3) = (1)/(2\sqrt{10}/3) = (3)/(2\sqrt{10}). This is equivalent to (3)/(1010)=(3)/(10)=(3/3)/(10/3)=(1)/(10/3)=(3)/(10)(3)/(\sqrt{10}\sqrt{10}) = (3)/(10) = (3/3)/(10/3) = (1)/(10/3) = (3)/(10). This matches one of the provided answer choices.

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