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Roselyn is driving to visit her family, who live $150$ kilometers away. Her average speed is $60$ kilometers per hour. The car's tank has $20$ liters of fuel at the beginning of the drive, and its fuel efficiency is $6$ kilometers per liter. Fuel costs $0.60$ dollars per liter. How long can Roselyn drive before she runs out of fuel?

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Pythagorean theorem

Full solution

Q. Roselyn is driving to visit her family, who live

150

kilometers away. Her average speed is

60

kilometers per hour. The car's tank has

20

liters of fuel at the beginning of the drive, and its fuel efficiency is

6

kilometers per liter. Fuel costs

0.60

dollars per liter. How long can Roselyn drive before she runs out of fuel?

Calculate Total Distance: Calculate the total distance Roselyn can drive with the fuel she has. $\newline$ Roselyn's car has $20$ liters of fuel and its fuel efficiency is $6$ kilometers per liter. To find the total distance she can drive, multiply the amount of fuel by the fuel efficiency. $\newline$ Total distance $=$ Fuel amount $\times$ Fuel efficiency $\newline$ Total distance $= 20$ liters $\times 6$ kilometers/liter
Perform Calculation: Perform the calculation for the total distance. $\newline$ Total distance = $20 \, \text{liters} \times 6 \, \text{kilometers/liter} = 120 \, \text{kilometers}$ $\newline$ Roselyn can drive $120 \, \text{kilometers}$ before she runs out of fuel.
Calculate Time: Calculate the time it will take for Roselyn to drive until she runs out of fuel. $\newline$ We know Roselyn's average speed is $60$ kilometers per hour. To find the time, divide the total distance she can drive by her average speed. $\newline$ Time = Total distance / Average speed $\newline$ Time = $120$ kilometers / $60$ kilometers/hour
Perform Calculation: Perform the calculation for the time. $\newline$ Time = $120 \, \text{kilometers} / 60 \, \text{kilometers/hour} = 2 \, \text{hours}$ $\newline$ Roselyn can drive for $2$ hours before she runs out of fuel.

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