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Imani's grandmother's house is 5 miles west of her own house down Main Street. While at her grandmother's, Imani decides to ride her bike farther west down Main Street at 10 miles per hour. Which equation best describes the distance, 
d, in miles, Imani is from home after 
t hours?
Choose 1 answer:
(A) 
d=5+10 t
(B) 
d=5-10 t
(c) 
d=5t+10
(D) 
d=5t-10

Imani's grandmother's house is 55 miles west of her own house down Main Street. While at her grandmother's, Imani decides to ride her bike farther west down Main Street at 1010 miles per hour. Which equation best describes the distance, d d , in miles, Imani is from home after t t hours?\newlineChoose 11 answer:\newline(A) d=5+10t d=5+10 t \newline(B) d=510t d=5-10 t \newline(C) d=5t+10 d=5 t+10 \newline(D) d=5t10 d=5 t-10

Full solution

Q. Imani's grandmother's house is 55 miles west of her own house down Main Street. While at her grandmother's, Imani decides to ride her bike farther west down Main Street at 1010 miles per hour. Which equation best describes the distance, d d , in miles, Imani is from home after t t hours?\newlineChoose 11 answer:\newline(A) d=5+10t d=5+10 t \newline(B) d=510t d=5-10 t \newline(C) d=5t+10 d=5 t+10 \newline(D) d=5t10 d=5 t-10
  1. Understand the problem: Understand the problem.\newlineImani starts 55 miles west of her house. When she rides her bike further west, she is moving away from her house. The rate at which she is moving away is 1010 miles per hour. We need to find an equation that represents the distance from her house after tt hours of riding her bike.
  2. Set up the equation: Set up the equation.\newlineSince Imani is already 55 miles away from her house, any additional distance she travels will be added to this initial distance. The rate of travel is 1010 miles per hour, so in tt hours, she will have traveled an additional 10×t10 \times t miles.
  3. Combine distances: Combine the initial distance with the distance traveled over time.\newlineThe total distance from Imani's house after tt hours is the initial 55 miles plus the distance traveled at a rate of 1010 miles per hour for tt hours. This gives us the equation d=5+10td = 5 + 10t.
  4. Check answer choices: Check the answer choices to see which one matches our equation.\newline(A) d=5+10td = 5 + 10t matches the equation we derived.\newline(B) d=510td = 5 - 10t would imply she is moving towards her house, which is incorrect.\newline(C) d=5t+10d = 5t + 10 does not correctly represent the initial distance and the rate of travel.\newline(D) d=5t10d = 5t - 10 also does not correctly represent the initial distance and the rate of travel.

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