Rewrite the expression as a product of four linear factors: (x^(2)-3x)^(2)-14(x^(2)-3x)+40 Answer:

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Rewrite the expression as a product of four linear factors:  (x^(2)-3x)^(2)-14(x^(2)-3x)+40 Answer:

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Identify Expression: Let's identify the expression we need to factor:  (x^2 - 3x)^2 - 14(x^2 - 3x) + 40 Notice that this is a quadratic in form, where (x^2 - 3x) is like a single variable. Let's substitute u = x^2 - 3x to make it clearer.Rewrite in terms of u: Rewrite the expression in terms of u: u^2 - 14u + 40 Now we have a quadratic equation in u that we can factor.Factor Quadratic Equation: Factor the quadratic equation: u^2 - 14u + 40 = (u - 10)(u - 4) We found two factors of the quadratic equation.Substitute back for x: Substitute back x^2 - 3x for u: (u - 10)(u - 4) = (x^2 - 3x - 10)(x^2 - 3x - 4) Now we have the expression in terms of x again, but we need to factor each quadratic further.Factor First Quadratic: Factor the first quadratic x^2 - 3x - 10: We look for two numbers that multiply to -10 and add to -3. These numbers are -5 and 2. x^2 - 3x - 10 = (x - 5)(x + 2)Factor Second Quadratic: Factor the second quadratic x^2 - 3x - 4: We look for two numbers that multiply to -4 and add to -3. These numbers are -4 and 1. x^2 - 3x - 4 = (x - 4)(x + 1)Combine Linear Factors: Combine all the linear factors to express the original expression: (x^2 - 3x - 10)(x^2 - 3x - 4) = (x - 5)(x + 2)(x - 4)(x + 1) We have rewritten the expression as a product of four linear factors.

Rewrite the expression as a product of four linear factors: $\newline$ $\left(x^{2}-3 x\right)^{2}-14\left(x^{2}-3 x\right)+40$ $\newline$ Answer:

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Rewrite the expression as a product of four linear factors:\newline(x2−3x)2−14(x2−3x)+40 \left(x^{2}-3 x\right)^{2}-14\left(x^{2}-3 x\right)+40 (x2−3x)2−14(x2−3x)+40\newlineAnswer:

Rewrite the expression as a product of four linear factors: $\newline$ $\left(x^{2}-3 x\right)^{2}-14\left(x^{2}-3 x\right)+40$ $\newline$ Answer: