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Rewrite the expression as a product of four linear factors:

(x^(2)-7x)^(2)+4(x^(2)-7x)-96
Answer:

Rewrite the expression as a product of four linear factors:\newline(x27x)2+4(x27x)96 \left(x^{2}-7 x\right)^{2}+4\left(x^{2}-7 x\right)-96 \newlineAnswer:

Full solution

Q. Rewrite the expression as a product of four linear factors:\newline(x27x)2+4(x27x)96 \left(x^{2}-7 x\right)^{2}+4\left(x^{2}-7 x\right)-96 \newlineAnswer:
  1. Identify and Recognize Quadratic Form: Identify the given expression and recognize that it resembles a quadratic in form, where the variable part is (x27x)(x^2 - 7x) instead of xx. The expression is: (x27x)2+4(x27x)96(x^2 - 7x)^2 + 4(x^2 - 7x) - 96
  2. Make Simplification Substitution: Let's make a substitution to simplify the expression. Let u=x27xu = x^2 - 7x. The expression then becomes: u2+4u96u^2 + 4u - 96 This is a quadratic equation in terms of uu.
  3. Factor Quadratic Equation: Factor the quadratic equation u2+4u96u^2 + 4u - 96. We need to find two numbers that multiply to 96-96 and add up to 44. These numbers are 1212 and 8-8. So, the factored form is (u+12)(u8)(u + 12)(u - 8).
  4. Substitute Back and Factor: Now, substitute back x27xx^2 - 7x for uu in the factored expression to get:\newline(x27x+12)(x27x8)(x^2 - 7x + 12)(x^2 - 7x - 8)
  5. Factor First Quadratic: We now need to factor each quadratic. Starting with x27x+12x^2 - 7x + 12, we look for two numbers that multiply to 1212 and add up to 7-7. These numbers are 3-3 and 4-4. So, the factored form is (x3)(x4)(x - 3)(x - 4).
  6. Factor Second Quadratic: Next, factor x27x8x^2 - 7x - 8. We look for two numbers that multiply to 8-8 and add up to 7-7. These numbers are 8-8 and 11. So, the factored form is (x8)(x+1)(x - 8)(x + 1).
  7. Combine Factors for Final Expression: Combine the factors from the previous steps to write the expression as a product of four linear factors: x3x - 3(x - 44\)(x - 88\)(x + 11\)

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