Q. Rewrite the expression as a product of four linear factors:(x2+3x)2−22(x2+3x)+72Answer:
Identify Given Quadratic Expression: Identify the given quadratic expression and recognize that it resembles a quadratic in form, where the variable part is (x2+3x) instead of a simple x. The expression is:(x2+3x)2−22(x2+3x)+72
Set Variable and Simplify: Notice that the expression is a quadratic in terms of x2+3x, which can be factored like a standard quadratic equation. Let's set y=x2+3x, then the expression becomes:y2−22y+72
Factor Quadratic Expression: Factor the quadratic expression y2−22y+72. We are looking for two numbers that multiply to 72 and add up to −22. These numbers are −18 and −4, so we can write:y2−22y+72=(y−18)(y−4)
Substitute Back and Simplify: Now, substitute back x2+3x for y to get the expression in terms of x: (y−18)(y−4) becomes ((x2+3x) - 18)((x2+3x) - 4)
Expand First Binomial: Expand each binomial to find the linear factors. For the first binomial, we have:(x2+3x−18)=(x2+6x−3x−18)=x(x+6)−3(x+6)=(x−3)(x+6)
Expand Second Binomial: Expand the second binomial to find the linear factors. For the second binomial, we have:(x2+3x−4)=(x2+4x−x−4)=x(x+4)−1(x+4)=(x−1)(x+4)
Combine Factors: Combine the factors from both binomials to express the original expression as a product of four linear factors: x−3(x + 6\)(x - 1\)(x + 4\)
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