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Rewrite the expression as a product of four linear factors:

(x^(2)+3x)^(2)-22(x^(2)+3x)+72
Answer:

Rewrite the expression as a product of four linear factors:\newline(x2+3x)222(x2+3x)+72 \left(x^{2}+3 x\right)^{2}-22\left(x^{2}+3 x\right)+72 \newlineAnswer:

Full solution

Q. Rewrite the expression as a product of four linear factors:\newline(x2+3x)222(x2+3x)+72 \left(x^{2}+3 x\right)^{2}-22\left(x^{2}+3 x\right)+72 \newlineAnswer:
  1. Identify Given Quadratic Expression: Identify the given quadratic expression and recognize that it resembles a quadratic in form, where the variable part is (x2+3x)(x^2 + 3x) instead of a simple xx. The expression is:\newline(x2+3x)222(x2+3x)+72(x^2 + 3x)^2 - 22(x^2 + 3x) + 72
  2. Set Variable and Simplify: Notice that the expression is a quadratic in terms of x2+3xx^2 + 3x, which can be factored like a standard quadratic equation. Let's set y=x2+3xy = x^2 + 3x, then the expression becomes:\newliney222y+72y^2 - 22y + 72
  3. Factor Quadratic Expression: Factor the quadratic expression y222y+72y^2 - 22y + 72. We are looking for two numbers that multiply to 7272 and add up to 22-22. These numbers are 18-18 and 4-4, so we can write:\newliney222y+72=(y18)(y4)y^2 - 22y + 72 = (y - 18)(y - 4)
  4. Substitute Back and Simplify: Now, substitute back x2+3xx^2 + 3x for yy to get the expression in terms of xx:
    (y18y - 18)(y4y - 4) becomes ((x2+3xx^2 + 3x) - 1818)((x2+3xx^2 + 3x) - 44)
  5. Expand First Binomial: Expand each binomial to find the linear factors. For the first binomial, we have:\newline(x2+3x18)=(x2+6x3x18)=x(x+6)3(x+6)=(x3)(x+6)(x^2 + 3x - 18) = (x^2 + 6x - 3x - 18) = x(x + 6) - 3(x + 6) = (x - 3)(x + 6)
  6. Expand Second Binomial: Expand the second binomial to find the linear factors. For the second binomial, we have:\newline(x2+3x4)=(x2+4xx4)=x(x+4)1(x+4)=(x1)(x+4)(x^2 + 3x - 4) = (x^2 + 4x - x - 4) = x(x + 4) - 1(x + 4) = (x - 1)(x + 4)
  7. Combine Factors: Combine the factors from both binomials to express the original expression as a product of four linear factors: x3x - 3(x + 66\)(x - 11\)(x + 44\)

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