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Rewrite the expression as a product of four linear factors:

(8x^(2)+11 x)^(2)-16(8x^(2)+11 x)-57
Answer:

Rewrite the expression as a product of four linear factors:\newline(8x2+11x)216(8x2+11x)57 \left(8 x^{2}+11 x\right)^{2}-16\left(8 x^{2}+11 x\right)-57 \newlineAnswer:

Full solution

Q. Rewrite the expression as a product of four linear factors:\newline(8x2+11x)216(8x2+11x)57 \left(8 x^{2}+11 x\right)^{2}-16\left(8 x^{2}+11 x\right)-57 \newlineAnswer:
  1. Identify and Recognize Quadratic Form: Identify the given expression and recognize that it resembles a quadratic in form, where the variable part is (8x2+11x)(8x^2 + 11x). The expression is: (8x2+11x)216(8x2+11x)57(8x^2 + 11x)^2 - 16(8x^2 + 11x) - 57 Let's denote u=8x2+11xu = 8x^2 + 11x, so the expression becomes: u216u57u^2 - 16u - 57
  2. Factor Quadratic Expression: Factor the quadratic expression u216u57u^2 - 16u - 57. We are looking for two numbers that multiply to 57-57 and add up to 16-16. The numbers that satisfy these conditions are 19-19 and +3+3. So we can factor the quadratic as: (u19)(u+3)(u - 19)(u + 3)
  3. Substitute and Expand: Now, substitute back 8x2+11x8x^2 + 11x for uu in each factor.\newline(8x2+11x19)(8x2+11x+3)(8x^2 + 11x - 19)(8x^2 + 11x + 3)
  4. Further Factorization Error: Each quadratic factor can be further factored into two linear factors. We will start with the first quadratic factor:\newline8x2+11x198x^2 + 11x - 19\newlineTo factor this, we need to find two numbers that multiply to 8(19)=1528*(-19) = -152 and add up to 1111.\newlineThe numbers that satisfy these conditions are 1919 and 8-8.\newlineHowever, we cannot directly factor this quadratic into linear factors because the numbers 1919 and 8-8 do not multiply to 152-152. This indicates a math error in the factorization process.

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