Bytelearn - cat image with glassesAI tutor

Welcome to Bytelearn!

Let’s check out your problem:

Rewrite the expression as a product of four linear factors:

(7x^(2)-10 x)^(2)-14(7x^(2)-10 x)-51
Answer:

Rewrite the expression as a product of four linear factors:\newline(7x210x)214(7x210x)51 \left(7 x^{2}-10 x\right)^{2}-14\left(7 x^{2}-10 x\right)-51 \newlineAnswer:

Full solution

Q. Rewrite the expression as a product of four linear factors:\newline(7x210x)214(7x210x)51 \left(7 x^{2}-10 x\right)^{2}-14\left(7 x^{2}-10 x\right)-51 \newlineAnswer:
  1. Identify Expression and Form: Identify the given expression and recognize that it resembles a quadratic in form, where the variable part is (7x210x)(7x^2 - 10x). The expression is: (7x210x)214(7x210x)51(7x^2 - 10x)^2 - 14(7x^2 - 10x) - 51 Let's set u=7x210xu = 7x^2 - 10x, so the expression becomes a quadratic in uu: u214u51u^2 - 14u - 51
  2. Set Variable and Simplify: Factor the quadratic expression u214u51u^2 - 14u - 51. We are looking for two numbers that multiply to 51-51 and add up to 14-14. The numbers that satisfy these conditions are 17-17 and 33, since (17)×3=51(-17) \times 3 = -51 and (17)+3=14(-17) + 3 = -14. So we can factor the quadratic as (u17)(u+3)(u - 17)(u + 3).
  3. Factor Quadratic Expression: Now, substitute back 7x210x7x^2 - 10x for uu in the factored form.\newlineWe get (7x210x17)(7x210x+3)(7x^2 - 10x - 17)(7x^2 - 10x + 3).
  4. Substitute and Expand: Next, we need to factor each of these quadratic expressions further to find the linear factors.\newlineStarting with 7x210x177x^2 - 10x - 17, we look for two numbers that multiply to 7×17=1197 \times -17 = -119 and add up to 10-10.\newlineThe numbers that satisfy these conditions are 17-17 and 77, since (17)×7=119(-17) \times 7 = -119 and (17)+7=10(-17) + 7 = -10.\newlineSo we can factor the quadratic as (7x+7)(x17)(7x + 7)(x - 17).
  5. Factor First Quadratic: Now, factor the second quadratic expression 7x210x+37x^2 - 10x + 3. We look for two numbers that multiply to 7×3=217 \times 3 = 21 and add up to 10-10. The numbers that satisfy these conditions are 7-7 and 3-3, since (7)×(3)=21(-7) \times (-3) = 21 and (7)+(3)=10(-7) + (-3) = -10. However, upon checking the multiplication, we find that 7-7 and 3-3 do not multiply to 2121. This is a math error.

More problems from Operations with rational exponents