Q. Rewrite the expression as a product of four linear factors:(7x2−10x)2−14(7x2−10x)−51Answer:
Identify Expression and Form: Identify the given expression and recognize that it resembles a quadratic in form, where the variable part is (7x2−10x). The expression is: (7x2−10x)2−14(7x2−10x)−51 Let's set u=7x2−10x, so the expression becomes a quadratic in u: u2−14u−51
Set Variable and Simplify: Factor the quadratic expression u2−14u−51. We are looking for two numbers that multiply to −51 and add up to −14. The numbers that satisfy these conditions are −17 and 3, since (−17)×3=−51 and (−17)+3=−14. So we can factor the quadratic as (u−17)(u+3).
Factor Quadratic Expression: Now, substitute back 7x2−10x for u in the factored form.We get (7x2−10x−17)(7x2−10x+3).
Substitute and Expand: Next, we need to factor each of these quadratic expressions further to find the linear factors.Starting with 7x2−10x−17, we look for two numbers that multiply to 7×−17=−119 and add up to −10.The numbers that satisfy these conditions are −17 and 7, since (−17)×7=−119 and (−17)+7=−10.So we can factor the quadratic as (7x+7)(x−17).
Factor First Quadratic: Now, factor the second quadratic expression 7x2−10x+3. We look for two numbers that multiply to 7×3=21 and add up to −10. The numbers that satisfy these conditions are −7 and −3, since (−7)×(−3)=21 and (−7)+(−3)=−10. However, upon checking the multiplication, we find that −7 and −3 do not multiply to 21. This is a math error.
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