Rewrite the expression as a product of four linear factors: (7x^(2)+15 x)^(2)-16(7x^(2)+15 x)-36 Answer:

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Rewrite the expression as a product of four linear factors:  (7x^(2)+15 x)^(2)-16(7x^(2)+15 x)-36 Answer:

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Identify Expression Form: Identify the given expression and recognize that it resembles a quadratic in form, where the variable part is (7x^2 + 15x). The expression is: (7x^2 + 15x)^2 - 16(7x^2 + 15x) - 36 Let's denote u = 7x^2 + 15x, so the expression becomes: u^2 - 16u - 36Denote Variable: Now, we need to factor the quadratic expression u^2 - 16u - 36. We are looking for two numbers that multiply to -36 and add up to -16. These numbers are -18 and +2. So we can write the quadratic as: (u - 18)(u + 2)Factor Quadratic Expression: Substitute back 7x^2 + 15x for u in the factored form to get: (7x^2 + 15x - 18)(7x^2 + 15x + 2)Substitute Variable Back: Now, we need to factor each quadratic expression further. We start with 7x^2 + 15x - 18. We look for two numbers that multiply to 7 * -18 = -126 and add up to 15. These numbers are 21 and -6. So we can write the quadratic as: (7x - 6)(x + 3)Factor First Quadratic: Next, we factor 7x^2 + 15x + 2. We look for two numbers that multiply to 7 * 2 = 14 and add up to 15. These numbers are 14 and 1. So we can write the quadratic as: (7x + 1)(x + 2)Factor Second Quadratic: Combine all the linear factors to express the original expression as a product of four linear factors: (7x - 6)(x + 3)(7x + 1)(x + 2)

Rewrite the expression as a product of four linear factors: $\newline$ $\left(7 x^{2}+15 x\right)^{2}-16\left(7 x^{2}+15 x\right)-36$ $\newline$ Answer:

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Rewrite the expression as a product of four linear factors:\newline(7x2+15x)2−16(7x2+15x)−36 \left(7 x^{2}+15 x\right)^{2}-16\left(7 x^{2}+15 x\right)-36 (7x2+15x)2−16(7x2+15x)−36\newlineAnswer:

Rewrite the expression as a product of four linear factors: $\newline$ $\left(7 x^{2}+15 x\right)^{2}-16\left(7 x^{2}+15 x\right)-36$ $\newline$ Answer: