Q. Rewrite the expression as a product of four linear factors:(6x2+19x)2−8(6x2+19x)−33Answer:
Identify Expression: Let's first identify the expression we need to factor: (6x2+19x)2−8(6x2+19x)−33This is a quadratic in form, where the variable part (6x2+19x) is squared. We can use a substitution to make it look like a standard quadratic equation. Let's let u=6x2+19x.
Substitution with u: Now we rewrite the expression in terms of u:u2−8u−33This is a quadratic equation that we can factor.
Rewrite in terms of u: We need to find two numbers that multiply to −33 and add up to −8. These numbers are −11 and 3.So we can write the quadratic as:(u−11)(u+3)
Factor quadratic: Now we substitute back 6x2+19x for u to get:(6x2+19x−11)(6x2+19x+3)
Substitute back for u: Each of these quadratic factors can be factored further. We start with the first one:6x2+19x−11We need to find two numbers that multiply to 6×−11=−66 and add up to 19. These numbers are 22 and −3.So we can write the quadratic as:(2x−1)(3x+11)
Factor first quadratic: Now we factor the second quadratic:6x2+19x+3We need to find two numbers that multiply to 6×3=18 and add up to 19. These numbers are 18 and 1.So we can write the quadratic as:(x+1)(6x+3)
Factor second quadratic: We can simplify the second factor further by taking out a common factor of 3:(x+1)(3)(2x+1)
Combine all factors: Now we combine all the factors to express the original expression as a product of four linear factors: \(2x - 1)(3x + 11)(x + 1)(2x + 1)\
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