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Rewrite the expression as a product of four linear factors:

(6x^(2)+19 x)^(2)-8(6x^(2)+19 x)-33
Answer:

Rewrite the expression as a product of four linear factors:\newline(6x2+19x)28(6x2+19x)33 \left(6 x^{2}+19 x\right)^{2}-8\left(6 x^{2}+19 x\right)-33 \newlineAnswer:

Full solution

Q. Rewrite the expression as a product of four linear factors:\newline(6x2+19x)28(6x2+19x)33 \left(6 x^{2}+19 x\right)^{2}-8\left(6 x^{2}+19 x\right)-33 \newlineAnswer:
  1. Identify Expression: Let's first identify the expression we need to factor: \newline(6x2+19x)28(6x2+19x)33(6x^2 + 19x)^2 - 8(6x^2 + 19x) - 33\newlineThis is a quadratic in form, where the variable part (6x2+19x)(6x^2 + 19x) is squared. We can use a substitution to make it look like a standard quadratic equation. Let's let u=6x2+19xu = 6x^2 + 19x.
  2. Substitution with u: Now we rewrite the expression in terms of uu:u28u33u^2 - 8u - 33This is a quadratic equation that we can factor.
  3. Rewrite in terms of uu: We need to find two numbers that multiply to 33-33 and add up to 8-8. These numbers are 11-11 and 33.\newlineSo we can write the quadratic as:\newline(u11)(u+3)(u - 11)(u + 3)
  4. Factor quadratic: Now we substitute back 6x2+19x6x^2 + 19x for uu to get:\newline(6x2+19x11)(6x2+19x+3)(6x^2 + 19x - 11)(6x^2 + 19x + 3)
  5. Substitute back for u: Each of these quadratic factors can be factored further. We start with the first one:\newline6x2+19x116x^2 + 19x - 11\newlineWe need to find two numbers that multiply to 6×11=666 \times -11 = -66 and add up to 1919. These numbers are 2222 and 3-3.\newlineSo we can write the quadratic as:\newline(2x1)(3x+11)(2x - 1)(3x + 11)
  6. Factor first quadratic: Now we factor the second quadratic:\newline6x2+19x+36x^2 + 19x + 3\newlineWe need to find two numbers that multiply to 6×3=186 \times 3 = 18 and add up to 1919. These numbers are 1818 and 11.\newlineSo we can write the quadratic as:\newline(x+1)(6x+3)(x + 1)(6x + 3)
  7. Factor second quadratic: We can simplify the second factor further by taking out a common factor of 33:(x+1)(3)(2x+1)(x + 1)(3)(2x + 1)
  8. Combine all factors: Now we combine all the factors to express the original expression as a product of four linear factors: \(2x - 11)(33x + 1111)(x + 11)(22x + 11)\

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