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Rewrite the expression as a product of four linear factors:

(3x^(2)-10 x)^(2)-10(3x^(2)-10 x)-39
Answer:

Rewrite the expression as a product of four linear factors:\newline(3x210x)210(3x210x)39 \left(3 x^{2}-10 x\right)^{2}-10\left(3 x^{2}-10 x\right)-39 \newlineAnswer:

Full solution

Q. Rewrite the expression as a product of four linear factors:\newline(3x210x)210(3x210x)39 \left(3 x^{2}-10 x\right)^{2}-10\left(3 x^{2}-10 x\right)-39 \newlineAnswer:
  1. Identify Expression: Identify the given expression and recognize that it resembles a quadratic in form, where the variable part is (3x210x)(3x^2 - 10x).\newlineThe expression is: (3x210x)210(3x210x)39(3x^2 - 10x)^2 - 10(3x^2 - 10x) - 39\newlineLet's denote u=3x210xu = 3x^2 - 10x, so the expression becomes:\newlineu210u39u^2 - 10u - 39
  2. Factor Quadratic: Factor the quadratic expression u210u39u^2 - 10u - 39. We are looking for two numbers that multiply to 39-39 and add up to 10-10. The numbers that satisfy these conditions are 13-13 and +3+3. So we can write the quadratic as: (u13)(u+3)(u - 13)(u + 3)
  3. Substitute and Simplify: Now, substitute back the original expression for uu, which is 3x210x3x^2 - 10x, into the factored form:\newline(3x210x13)(3x210x+3)(3x^2 - 10x - 13)(3x^2 - 10x + 3)
  4. Factor First Quadratic: Notice that each quadratic factor can be further factored into two linear factors. We will start with the first quadratic factor:\newline3x210x133x^2 - 10x - 13\newlineTo factor this, we need to find two numbers that multiply to 3(13)=393*(-13) = -39 and add up to 10-10. These numbers are the same as before, 13-13 and +3+3, but we need to consider the coefficient of x2x^2, which is 33.\newlineWe can write the factorization as:\newline(3x+1)(x13)(3x + 1)(x - 13)
  5. Factor Second Quadratic: Now, factor the second quadratic factor:\newline3x210x+33x^2 - 10x + 3\newlineAgain, we need to find two numbers that multiply to 3×3=93\times3 = 9 and add up to 10-10. These numbers are 9-9 and 1-1.\newlineWe can write the factorization as:\newline(3x1)(x3)(3x - 1)(x - 3)
  6. Combine Linear Factors: Combine all the linear factors to express the original expression as a product of four linear factors:\newline(3x+1)(x13)(3x1)(x3)(3x + 1)(x - 13)(3x - 1)(x - 3)

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