Rewrite the expression as a product of four linear factors: (10x^(2)+3x)^(2)-19(10x^(2)+3x)+18 Answer:

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Rewrite the expression as a product of four linear factors:  (10x^(2)+3x)^(2)-19(10x^(2)+3x)+18 Answer:

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Identify expression as quadratic: Identify the given expression and recognize that it resembles a quadratic in form, where the variable part is (10x^2 + 3x) instead of a simple x. The expression is a quadratic in terms of (10x^2 + 3x).Rewrite as quadratic equation: Rewrite the expression as a quadratic equation: Let u = 10x^2 + 3x. Then the expression becomes u^2 - 19u + 18.Factor the quadratic: Factor the quadratic equation: We need to find two numbers that multiply to 18 and add up to -19. These numbers are -1 and -18. So we can write the quadratic as (u - 1)(u - 18).Substitute back for u: Substitute back for u: Replace u with (10x^2 + 3x) in the factored form to get ((10x^2 + 3x) - 1)((10x^2 + 3x) - 18).Expand linear factors: Expand each linear factor: We need to simplify ((10x^2 + 3x) - 1) and ((10x^2 + 3x) - 18) to get the linear factors. For the first factor, (10x^2 + 3x - 1), we can't simplify it further, so it remains as is. For the second factor, (10x^2 + 3x - 18), we also can't simplify it further, so it remains as is.Recognize factors are quadratic: Recognize that the factors (10x^2 + 3x - 1) and (10x^2 + 3x - 18) are not linear, but quadratic. We need to factor each of these further to get linear factors.Factor first quadratic: Factor the first quadratic: We need to factor 10x^2 + 3x - 1. This does not factor nicely, and we would typically use the quadratic formula to find its roots. However, since we are looking for linear factors and this is a homework problem, it's likely that there is a simpler solution. We should check for a mistake in the previous steps before proceeding.

Rewrite the expression as a product of four linear factors: $\newline$ $\left(10 x^{2}+3 x\right)^{2}-19\left(10 x^{2}+3 x\right)+18$ $\newline$ Answer:

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Rewrite the expression as a product of four linear factors:\newline(10x2+3x)2−19(10x2+3x)+18 \left(10 x^{2}+3 x\right)^{2}-19\left(10 x^{2}+3 x\right)+18 (10x2+3x)2−19(10x2+3x)+18\newlineAnswer:

Rewrite the expression as a product of four linear factors: $\newline$ $\left(10 x^{2}+3 x\right)^{2}-19\left(10 x^{2}+3 x\right)+18$ $\newline$ Answer: