Bytelearn - cat image with glassesAI tutor

Welcome to Bytelearn!

Let’s check out your problem:

Rania is riding the ferris wheel.
Her vertical height 
H(t) (in 
m ) off the ground as a function of time 
t (in seconds) can be modeled by a sinusoidal expression of the form 
a*cos(b*t)+d.
At 
t=0, when she starts moving, she is at a height of 
10m off the ground, which is as low as she goes. After 
20 pi seconds, she reaches her maximum height of 
30m.
Find 
H(t).

t should be in radians.

H(t)=

Rania is riding the ferris wheel.\newlineHer vertical height H(t) H(t) (in m \mathrm{m} ) off the ground as a function of time t t (in seconds) can be modeled by a sinusoidal expression of the form acos(bt)+d a \cdot \cos (b \cdot t)+d .\newlineAt t=0 t=0 , when she starts moving, she is at a height of 10 m 10 \mathrm{~m} off the ground, which is as low as she goes. After 20π 20 \pi seconds, she reaches her maximum height of 30 m 30 \mathrm{~m} .\newlineFind H(t) H(t) .\newlinet t should be in radians.\newlineH(t)= H(t)=

Full solution

Q. Rania is riding the ferris wheel.\newlineHer vertical height H(t) H(t) (in m \mathrm{m} ) off the ground as a function of time t t (in seconds) can be modeled by a sinusoidal expression of the form acos(bt)+d a \cdot \cos (b \cdot t)+d .\newlineAt t=0 t=0 , when she starts moving, she is at a height of 10 m 10 \mathrm{~m} off the ground, which is as low as she goes. After 20π 20 \pi seconds, she reaches her maximum height of 30 m 30 \mathrm{~m} .\newlineFind H(t) H(t) .\newlinet t should be in radians.\newlineH(t)= H(t)=
  1. Initial Height Determination: Rania's lowest height is 10m10\,\text{m} at t=0t=0, so d=10d=10.
  2. Amplitude Calculation: The maximum height is 30m30\,\text{m}, so the amplitude aa is half the difference between max and min height, a=(3010)/2=10a=(30-10)/2=10.
  3. Period Calculation: Since the ferris wheel takes 20π20 \pi seconds to complete a full cycle, the period TT is 20π20 \pi seconds. The value of bb is found using b=2π/Tb=2\pi/T, so b=2π/(20π)=1/10b=2\pi/(20\pi)=1/10.
  4. Function Derivation: The function H(t)H(t) is H(t)=acos(bt)+dH(t)=a\cdot\cos(b\cdot t)+d. Substituting the values of aa, bb, and dd, we get H(t)=10cos((1/10)t)+10H(t)=10\cdot\cos((1/10)\cdot t)+10.

More problems from Solve quadratic equations: word problems