Point N is located at -9 . Points O and P are each 7 units away from Point N. Where are O and P located? O= P=

Given Data: Given that Point N is located at -9 on a number line, and Points O and P are each 7 units away from Point N, we need to find two points that are 7 units away from -9. One will be to the left (a negative direction) and one will be to the right (a positive direction) on the number line.Find Point O: To find Point O, which is 7 units to the left of Point N, we subtract 7 from the position of Point N. Calculation: -9 - 7 = -16 Point O is located at -16.Find Point P: To find Point P, which is 7 units to the right of Point N, we add 7 to the position of Point N. Calculation: -9 + 7 = -2 Point P is located at -2.

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Point
N is located at -9 . Points
O and
P are each 7 units away from Point
N. Where are
O and
P located?

O=

P=

Point $\mathrm{N}$ is located at $-9$ . Points $\mathrm{O}$ and $\mathrm{P}$ are each $7$ units away from Point $\mathrm{N}$ . Where are $\mathrm{O}$ and $\mathrm{P}$ located? $\newline$ $\mathrm{O}=\square \quad \mathrm{P}= \square$

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Algebra 1

Write and solve inverse variation equations

Full solution

Q. Point

\mathrm{N}

is located at

-9

. Points

\mathrm{O}

and

\mathrm{P}

are each

7

units away from Point

\mathrm{N}

. Where are

\mathrm{O}

and

\mathrm{P}

located?

\newline

\mathrm{O}=\square \quad \mathrm{P}= \square

Given Data: Given that Point $N$ is located at $-9$ on a number line, and Points $O$ and $P$ are each $7$ units away from Point $N$ , we need to find two points that are $7$ units away from $-9$ . One will be to the left (a negative direction) and one will be to the right (a positive direction) on the number line.
Find Point O: To find Point O, which is $7$ units to the left of Point N, we subtract $7$ from the position of Point N. $\newline$ Calculation: $-9 - 7 = -16$ $\newline$ Point O is located at $-16$ .
Find Point P: To find Point P, which is $7$ units to the right of Point N, we add $7$ to the position of Point N. $\newline$ Calculation: $-9 + 7 = -2$ $\newline$ Point P is located at $-2$ .