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F=[[2,3],[0,5],[-1,-1]] and

D=[[-1,0],[4,2]]
Let 
H=FD. Find 
H.

H=

F=[2amp;30amp;51amp;1] F=\left[\begin{array}{rr}2 & 3 \\ 0 & 5 \\ -1 & -1\end{array}\right] and D=[1amp;04amp;2] \mathrm{D}=\left[\begin{array}{rr} -1 & 0 \\ 4 & 2 \end{array}\right] \newlineLet H=FD \mathrm{H}=\mathrm{FD} . Find H \mathrm{H} .\newlineH= \mathbf{H}=

Full solution

Q. F=[230511] F=\left[\begin{array}{rr}2 & 3 \\ 0 & 5 \\ -1 & -1\end{array}\right] and D=[1042] \mathrm{D}=\left[\begin{array}{rr} -1 & 0 \\ 4 & 2 \end{array}\right] \newlineLet H=FD \mathrm{H}=\mathrm{FD} . Find H \mathrm{H} .\newlineH= \mathbf{H}=
  1. Understand matrix multiplication rules: Understand matrix multiplication rules.\newlineTo multiply two matrices, the number of columns in the first matrix must be equal to the number of rows in the second matrix. The resulting matrix will have the same number of rows as the first matrix and the same number of columns as the second matrix.
  2. Verify matrix multiplication for FF and DD: Verify if the matrices FF and DD can be multiplied.\newlineMatrix FF has dimensions 3×23 \times 2 (33 rows and 22 columns), and matrix DD has dimensions 2×22 \times 2 (22 rows and 22 columns). Since the number of columns in FF is equal to the number of rows in DD, we can multiply FF by DD.
  3. Set up matrix multiplication for F and D: Set up the multiplication of matrices FF and DD. To multiply FF by DD, we will take the dot product of the rows of FF with the columns of DD. This will give us a new matrix HH with dimensions 3×23 \times 2.
  4. Calculate first element of matrix \newlineHH: Calculate the first element of matrix \newlineHH.\newlineMultiply the first row of \newlineFF by the first column of \newlineDD:\newline\newlineH[1,1]=(2×1)+(3×4)=2+12=10H[1,1] = (2 \times -1) + (3 \times 4) = -2 + 12 = 10
  5. Calculate second element of first row of H: Calculate the second element of the first row of matrix HH. Multiply the first row of FF by the second column of DD: H[1,2]=(2×0)+(3×2)=0+6=6H[1,2] = (2 \times 0) + (3 \times 2) = 0 + 6 = 6
  6. Calculate first element of second row of H: Calculate the first element of the second row of matrix HH. Multiply the second row of FF by the first column of DD: H[2,1]=(0×1)+(5×4)=0+20=20H[2,1] = (0 \times -1) + (5 \times 4) = 0 + 20 = 20
  7. Calculate second element of second row of H: Calculate the second element of the second row of matrix HH. Multiply the second row of FF by the second column of DD: H[2,2]=(0×0)+(5×2)=0+10=10H[2,2] = (0 \times 0) + (5 \times 2) = 0 + 10 = 10
  8. Calculate first element of third row of H: Calculate the first element of the third row of matrix HH. Multiply the third row of FF by the first column of DD: H[3,1]=(1×1)+(1×4)=14=3H[3,1] = (-1 \times -1) + (-1 \times 4) = 1 - 4 = -3
  9. Calculate second element of third row of H: Calculate the second element of the third row of matrix HH. Multiply the third row of FF by the second column of DD: H[3,2]=(1×0)+(1×2)=02=2H[3,2] = (-1 \times 0) + (-1 \times 2) = 0 - 2 = -2
  10. Combine elements to form matrix H: Combine all the elements to form matrix HH.H=[10amp;6 20amp;10 3amp;2]H = \left[\begin{array}{cc}10 & 6 \ 20 & 10 \ -3 & -2\end{array}\right]

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