C=[[-1],[-2],[2]]" and "D=[[2,1]] Let H=CD. Find H. H=

Define Matrices C and D: Define the matrices C and D. Matrix C is a 3x1 matrix, and matrix D is a 1x2 matrix. C = [[-1], [-2], [2]] D = [[2, 1]]Check Matrix Multiplication: Determine if matrix multiplication is possible. For matrix multiplication, the number of columns in the first matrix must be equal to the number of rows in the second matrix. Matrix C has 1 column, and matrix D has 1 row, so multiplication is possible.Multiply C by D: Multiply matrix C by matrix D. To multiply C by D, we take each element of C and multiply it by each element of D, then sum the products for each row of C to get the corresponding row in matrix H. H = [[-1 * 2, -1 * 1], [-2 * 2, -2 * 1], [2 * 2, 2 * 1]]Calculate Each Element: Perform the calculations for each element. Calculate each element of matrix H. H = [[-2, -1], [-4, -2], [4, 2]]Write Final Matrix H: Write the final matrix H. The resulting matrix H after the multiplication is: H = [[-2, -1], [-4, -2], [4, 2]]

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C=[[-1],[-2],[2]]" and "D=[[2,1]]
Let
H=CD. Find
H.

H=

$\mathrm{C}=\left[\begin{array}{r} -1 \\ -2 \\ 2 \end{array}\right] \text { and } \mathrm{D}=\left[\begin{array}{ll} 2 & 1 \end{array}\right]$ $\newline$ Let $\mathrm{H}=\mathrm{CD}$ . Find $\mathrm{H}$ . $\newline$ $\mathbf{H}=$

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Algebra 1

Write and solve direct variation equations

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\mathrm{C}=\left[\begin{array}{r} -1 \\ -2 \\ 2 \end{array}\right] \text { and } \mathrm{D}=\left[\begin{array}{ll} 2 & 1 \end{array}\right]

\newline

Let

\mathrm{H}=\mathrm{CD}

. Find

\mathrm{H}

\newline

\mathbf{H}=

Define Matrices C and D: Define the matrices C and D. $\newline$ Matrix C is a $3 \times 1$ matrix, and matrix D is a $1 \times 2$ matrix. $\newline$ $C = \begin{bmatrix} -1 \ -2 \ 2 \end{bmatrix}$ $\newline$ $D = \begin{bmatrix} 2 & 1 \end{bmatrix}$
Check Matrix Multiplication: Determine if matrix multiplication is possible. $\newline$ For matrix multiplication, the number of columns in the first matrix must be equal to the number of rows in the second matrix. Matrix $C$ has $1$ column, and matrix $D$ has $1$ row, so multiplication is possible.
Multiply $C$ by $D$ : Multiply matrix $C$ by matrix $D$ . To multiply $C$ by $D$ , we take each element of $C$ and multiply it by each element of $D$ , then sum the products for each row of $C$ to get the corresponding row in matrix $H$ . $D$ $0$
Calculate Each Element: Perform the calculations for each element. $\newline$ Calculate each element of matrix $H$ . $\newline$ H = \left[\begin{array}{cc}$\newline-2 & -1 (\newline$-4 & -2 (\newline\)4 & 2 $\newline$ \end{array}\right]\)
Write Final Matrix $H$ : Write the final matrix $H$ . The resulting matrix $H$ after the multiplication is: $H = [[-2, -1], [-4, -2], [4, 2]]$