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Perform the operation and simplify the answer fully.

(10)/(9x^(3))÷(5)/(7x^(2))
Answer:

Perform the operation and simplify the answer fully.\newline109x3÷57x2 \frac{10}{9 x^{3}} \div \frac{5}{7 x^{2}} \newlineAnswer:

Full solution

Q. Perform the operation and simplify the answer fully.\newline109x3÷57x2 \frac{10}{9 x^{3}} \div \frac{5}{7 x^{2}} \newlineAnswer:
  1. Rewrite Division: Rewrite the division of fractions as multiplication by the reciprocal.\newlineTo divide by a fraction, you multiply by its reciprocal. The reciprocal of (5)/(7x2)(5)/(7x^{2}) is (7x2)/(5)(7x^{2})/(5).
  2. Set Up Multiplication: Set up the multiplication of the two fractions. 109x3×7x25\frac{10}{9x^{3}} \times \frac{7x^{2}}{5}
  3. Multiply Numerators and Denominators: Multiply the numerators and the denominators separately.\newline(10×7x2)/(9x3×5)(10 \times 7x^{2}) / (9x^{3} \times 5)
  4. Perform Multiplication: Perform the multiplication in the numerator and the denominator.\newline70x245x3\frac{70x^{2}}{45x^{3}}
  5. Simplify Fraction: Simplify the fraction by canceling common factors.\newlineBoth the numerator and the denominator have common factors of 55 and x2x^{2}.\newline(70/5)x2(45/5)x3\frac{(70/5)x^{2}}{(45/5)x^{3}}
  6. Simplify Numbers and Terms: Simplify the numbers and the xx terms separately.14x29x3\frac{14x^{2}}{9x^{3}}
  7. Apply Exponent Laws: Apply the laws of exponents to simplify the xx terms.\newlineWhen dividing like bases, subtract the exponents: x2x3=x23=x1\frac{x^{2}}{x^{3}} = x^{2-3} = x^{-1}.\newline149x1\frac{14}{9x^{1}}
  8. Rewrite with Positive Exponent: Rewrite the expression with a positive exponent.\newlineSince x1x^{-1} is the same as 1x\frac{1}{x}, the final simplified form is:\newline149x\frac{14}{9x}

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