Perform the following operation and express in simplest form. (x^(4)-6x^(3))/(x^(2)-14 x+48)÷(x)/(x^(2)-64) Answer:

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Perform the following operation and express in simplest form.  (x^(4)-6x^(3))/(x^(2)-14 x+48)÷(x)/(x^(2)-64) Answer:

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Factor Denominator: Factor the denominator of the first fraction and the numerator and denominator of the second fraction. The denominator x^2 - 14x + 48 can be factored into (x-6)(x-8) because 6*8 = 48 and 6+8 = 14. The numerator x of the second fraction remains the same. The denominator x^2 - 64 is a difference of squares and can be factored into (x+8)(x-8).Rewrite as Multiplication: Rewrite the division as multiplication by the reciprocal. The division of two fractions can be rewritten as the multiplication of the first fraction by the reciprocal of the second fraction. (x^(4)-6x^(3))/(x^(2)-14x+48) ÷ (x)/(x^(2)-64) = (x^(4)-6x^(3))/(x^(2)-14x+48) * (x^(2)-64)/(x)Factor Numerator: Factor the numerator of the first fraction if possible. The numerator x^4 - 6x^3 can be factored by taking out the common factor x^3, which gives us x^3(x - 6).Cancel Common Factors: Cancel out common factors. Now we have x^3(x - 6)/(x-6)(x-8) * (x+8)(x-8)/x. We can cancel out the common factors (x-6) and (x-8) from the numerator and denominator. This leaves us with x^3/(x-8) * (x+8)/x.Cancel Factor of x: Cancel out the common factor of x. We can cancel out the x from the numerator of the second fraction and the denominator of the first fraction. This leaves us with x^2 * (x+8).Multiply Expressions: Multiply the remaining expressions. Now we multiply x^2 by (x+8) to get the final simplified form. x^2 * (x+8) = x^3 + 8x^2.

Perform the following operation and express in simplest form. $\newline$ $\frac{x^{4}-6 x^{3}}{x^{2}-14 x+48} \div \frac{x}{x^{2}-64}$ $\newline$ Answer:

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Perform the following operation and express in simplest form.\newlinex4−6x3x2−14x+48÷xx2−64 \frac{x^{4}-6 x^{3}}{x^{2}-14 x+48} \div \frac{x}{x^{2}-64} x2−14x+48x4−6x3​÷x2−64x​\newlineAnswer:

Perform the following operation and express in simplest form. $\newline$ $\frac{x^{4}-6 x^{3}}{x^{2}-14 x+48} \div \frac{x}{x^{2}-64}$ $\newline$ Answer: