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Perform the following operation and express in simplest form.

(6x+12)/(x^(2)+11 x+18)÷(x+4)/(x^(2)+6x-27)
Answer:

Perform the following operation and express in simplest form.\newline6x+12x2+11x+18÷x+4x2+6x27 \frac{6 x+12}{x^{2}+11 x+18} \div \frac{x+4}{x^{2}+6 x-27} \newlineAnswer:

Full solution

Q. Perform the following operation and express in simplest form.\newline6x+12x2+11x+18÷x+4x2+6x27 \frac{6 x+12}{x^{2}+11 x+18} \div \frac{x+4}{x^{2}+6 x-27} \newlineAnswer:
  1. Identify and Rewrite Division: Identify the given expression and rewrite the division as multiplication by the reciprocal of the second fraction.\newline(6x+12)/(x2+11x+18)÷(x+4)/(x2+6x27)=(6x+12)/(x2+11x+18)×(x2+6x27)/(x+4)(6x+12)/(x^2+11x+18) \div (x+4)/(x^2+6x-27) = (6x+12)/(x^2+11x+18) \times (x^2+6x-27)/(x+4)
  2. Factor First Fraction: Factor the numerator and denominator of the first fraction. \newline6x+126x+12 can be factored as 6(x+2)6(x+2).\newlinex2+11x+18x^2+11x+18 can be factored as (x+9)(x+2)(x+9)(x+2).\newlineThe first fraction becomes 6(x+2)(x+9)(x+2)\frac{6(x+2)}{(x+9)(x+2)}.
  3. Factor Second Fraction: Factor the numerator and denominator of the second fraction. x2+6x27x^2+6x-27 can be factored as (x+9)(x3)(x+9)(x-3). The second fraction becomes (x+9)(x3)/(x+4)(x+9)(x-3)/(x+4).
  4. Combine and Cancel Factors: Combine the factored forms and cancel out common factors.\newline(6(x+2)/((x+9)(x+2)))×((x+9)(x3)/(x+4))=6(x+9)(x3)(x+9)(x+4)(6(x+2)/((x+9)(x+2))) \times ((x+9)(x-3)/(x+4)) = \frac{6(x+9)(x-3)}{(x+9)(x+4)}\newlineHere, (x+2)(x+2) and (x+9)(x+9) cancel out from the numerator and denominator.
  5. Simplify Remaining Expression: Simplify the remaining expression.\newlineAfter canceling, we are left with 6(x3)x+4\frac{6(x-3)}{x+4}.
  6. Check for Further Simplification: Check for any further simplification or common factors. There are no common factors left, and the expression is in its simplest form.

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