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Perform the following operation and express in simplest form.

(x+6)/(x-9)÷(x^(2)-3x-54)/(x^(2)-18 x+81)
Answer:

Perform the following operation and express in simplest form.\newlinex+6x9÷x23x54x218x+81 \frac{x+6}{x-9} \div \frac{x^{2}-3 x-54}{x^{2}-18 x+81} \newlineAnswer:

Full solution

Q. Perform the following operation and express in simplest form.\newlinex+6x9÷x23x54x218x+81 \frac{x+6}{x-9} \div \frac{x^{2}-3 x-54}{x^{2}-18 x+81} \newlineAnswer:
  1. Identify Given Expression: Identify the given expression and rewrite the division as multiplication by the reciprocal of the second fraction.\newlineThe expression is (x+6)/(x9)÷(x23x54)/(x218x+81)(x+6)/(x-9) \div (x^2-3x-54)/(x^2-18x+81), which can be rewritten as (x+6)/(x9)×(x218x+81)/(x23x54)(x+6)/(x-9) \times (x^2-18x+81)/(x^2-3x-54).
  2. Factor Second Fraction: Factor both the numerator and the denominator of the second fraction.\newlineThe numerator x218x+81x^2-18x+81 can be factored as (x9)(x9)(x-9)(x-9) or (x9)2(x-9)^2.\newlineThe denominator x23x54x^2-3x-54 can be factored as (x9)(x+6)(x-9)(x+6).
  3. Rewrite with Factored Terms: Rewrite the expression with the factored terms.\newlineThe expression now looks like (x+6)/(x9)×((x9)(x9))/((x9)(x+6))(x+6)/(x-9) \times ((x-9)(x-9))/((x-9)(x+6)).
  4. Cancel Common Terms: Cancel out the common terms in the numerator and the denominator.\newlineThe (x+6)(x+6) terms cancel each other out, and one of the (x9)(x-9) terms cancels out, leaving us with 1(x9)×(x9)\frac{1}{(x-9)} \times (x-9).
  5. Simplify Remaining Expression: Simplify the remaining expression.\newlineAfter canceling out, the expression simplifies to 11, since 1(x9)×(x9)=1\frac{1}{(x-9)} \times (x-9) = 1.

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