p(t)=80(1.05)tThe function models p, the population, in thousands, of City Xt years after 2000. Based on the model, what is the approximate population, in thousands, of City X in 2010 ?Choose 1 answer:(A) 88(B) 130(C) 212(D) 840
Q. p(t)=80(1.05)tThe function models p, the population, in thousands, of City Xt years after 2000. Based on the model, what is the approximate population, in thousands, of City X in 2010 ?Choose 1 answer:(A) 88(B) 130(C) 212(D) 840
Identify the given function: Identify the given function and what it represents.The function p(t)=80(1.05)t models the population of City X, in thousands, t years after 2000.
Determine the value of : Determine the value of for the year .\newlineSince t represents the number of years after 200020002000, for the year 201020102010, t = 201020102010 - 200020002000 = 101010 years.
Substitute the value of t: Substitute the value of t into the function to find the population in 201020102010.\newlinep(101010) = 808080(111.050505)^{101010}
Calculate the population in 201020102010: Calculate the population in 201020102010 using the function. p(10)=80(1.05)10≈80×1.62889≈130.3112p(10) = 80(1.05)^{10} \approx 80 \times 1.62889 \approx 130.3112p(10)=80(1.05)10≈80×1.62889≈130.3112
Round the population to the nearest thousand: Round the population to the nearest thousand as the answer choices are in whole numbers.\newlineThe approximate population in thousands is 130130130.
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