Bytelearn - cat image with glassesAI tutor

Welcome to Bytelearn!

Let’s check out your problem:

outlook
Spotily: Węb Play
ro
Vour Sets
A. Adobe Acróbat
Algebra II PD 7
DeltaMath
Given the matrices 
A and 
B shown below, find 
B-(1)/(6)A.

A=[[-24,24],[6,-30],[-18,12],[-36,-18]]quad B=[[4,-9],[6,1],[-12,-11],[-4,0]]
Answer
Attempt
2 out of
Rows: 4

⊖o+
Columns: 2

theta

[[8,-8],[.5,8]]

outlook\newlineSpotily: Węb Play\newlinero\newlineVour Sets\newlineA. Adobe Acróbat\newlineAlgebra II PD 77\newlineDeltaMath\newlineGiven the matrices A A and B B shown below, find B16A B-\frac{1}{6} A .\newlineA=[24amp;246amp;3018amp;1236amp;18]B=[4amp;96amp;112amp;114amp;0] A=\left[\begin{array}{cc} -24 & 24 \\ 6 & -30 \\ -18 & 12 \\ -36 & -18 \end{array}\right] \quad B=\left[\begin{array}{cc} 4 & -9 \\ 6 & 1 \\ -12 & -11 \\ -4 & 0 \end{array}\right] \newlineAnswer\newlineAttempt\newline22 out of\newlineRows: 44\newline \ominus \oplus \newlineColumns: 22\newlineθ \boldsymbol{\theta} \newline[8amp;8.5amp;8] \left[\begin{array}{cc} 8 & -8 \\ .5 & 8 \end{array}\right]

Full solution

Q. outlook\newlineSpotily: Węb Play\newlinero\newlineVour Sets\newlineA. Adobe Acróbat\newlineAlgebra II PD 77\newlineDeltaMath\newlineGiven the matrices A A and B B shown below, find B16A B-\frac{1}{6} A .\newlineA=[242463018123618]B=[4961121140] A=\left[\begin{array}{cc} -24 & 24 \\ 6 & -30 \\ -18 & 12 \\ -36 & -18 \end{array}\right] \quad B=\left[\begin{array}{cc} 4 & -9 \\ 6 & 1 \\ -12 & -11 \\ -4 & 0 \end{array}\right] \newlineAnswer\newlineAttempt\newline22 out of\newlineRows: 44\newline \ominus \oplus \newlineColumns: 22\newlineθ \boldsymbol{\theta} \newline[88.58] \left[\begin{array}{cc} 8 & -8 \\ .5 & 8 \end{array}\right]
  1. Identify Matrices A and B: Identify matrix AA and matrix BB from the problem statement.\newlineMatrix A=[24amp;24 6amp;30 18amp;12 36amp;18]A = \left[\begin{array}{cc} -24 & 24 \ 6 & -30 \ -18 & 12 \ -36 & -18 \end{array}\right]\newlineMatrix B=[4amp;9 6amp;1 12amp;11 4amp;0]B = \left[\begin{array}{cc} 4 & -9 \ 6 & 1 \ -12 & -11 \ -4 & 0 \end{array}\right]
  2. Calculate (16)A(\frac{1}{6})A: Calculate (16)A(\frac{1}{6})A by multiplying each element of AA by 16\frac{1}{6}.(16)A=[246amp;246 66amp;306 186amp;126 366amp;186](\frac{1}{6})A = \left[\begin{array}{cc}-\frac{24}{6} & \frac{24}{6} \ \frac{6}{6} & -\frac{30}{6} \ -\frac{18}{6} & \frac{12}{6} \ -\frac{36}{6} & -\frac{18}{6}\end{array}\right] =[4amp;4 1amp;5 3amp;2 6amp;3]= \left[\begin{array}{cc}-4 & 4 \ 1 & -5 \ -3 & 2 \ -6 & -3\end{array}\right]
  3. Subtract (16)A(\frac{1}{6})A from BB: Subtract (16)A(\frac{1}{6})A from BB.B(16)A=[[4(4),94],[61,1(5)],[12(3),112],[4(6),0(3)]]B - (\frac{1}{6})A = [[4 - (-4), -9 - 4], [6 - 1, 1 - (-5)], [-12 - (-3), -11 - 2], [-4 - (-6), 0 - (-3)]] = [[44 + 44, 9-9 - 44], [66 - 11, 11 + 55], [12-12 + 33, 11-11 - 22], [4-4 + 66, 00 + 33]] = [[88, 13-13], [55, 66], [9-9, 13-13], [22, 33]]

More problems from Compare linear and exponential growth