Multiply. Write your answer in simplest form. -sqrt 3(-9 + sqrt 3) ______

Distribute -sqrt(3): Distribute -sqrt(3) to both terms inside the parentheses. -sqrt(3)(-9 + sqrt(3)) = -sqrt(3)*(-9) + -sqrt(3)*(sqrt(3))Multiply -sqrt(3) by -9: Multiply -sqrt(3) by -9. -sqrt(3)*(-9) = 9*sqrt(3)Multiply -sqrt(3) by sqrt(3): Multiply -sqrt(3) by sqrt(3). -sqrt(3)*sqrt(3) = -(sqrt(3))^2 Since the square root and the square cancel each other out, we have: -(sqrt(3))^2 = -3Combine results: Combine the results from Step 2 and Step 3. 9*sqrt(3) - 3

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Multiply. Write your answer in simplest form. $\newline$ $-\sqrt{3}(-9 + \sqrt{3})$

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Algebra 2

Simplify radical expressions using the distributive property

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Q. Multiply. Write your answer in simplest form.

\newline

-\sqrt{3}(-9 + \sqrt{3})

Distribute $-\sqrt{3}$ : Distribute $-\sqrt{3}$ to both terms inside the parentheses.-\sqrt{$3$}(\(-9 + \sqrt{ $3$ }) = -\sqrt{ $3$ }( $-9$ ) + -\sqrt{ $3$ }(\sqrt{ $3$ })
Multiply $-\sqrt{3}$ by $-9$ : Multiply $-\sqrt{3}$ by $-9$ . $\newline$ $-\sqrt{3}\cdot(-9) = 9\sqrt{3}$
Multiply $-\sqrt{3}$ by $\sqrt{3}$ : Multiply $-\sqrt{3}$ by $\sqrt{3}$ . $\newline$ $-\sqrt{3}\times\sqrt{3} = -(\sqrt{3})^2$ $\newline$ Since the square root and the square cancel each other out, we have: $\newline$ $-(\sqrt{3})^2 = -3$
Combine results: Combine the results from Step $2$ and Step $3$ . $\newline$ $9\sqrt{3} - 3$