Q. Let y=ex.Find dxdy.Choose 1 answer:(A) 2ex(B) ex(C) xex−1(D) 2ex1
Express Function in Terms of x: First, let's express the function y in terms of x using the square root and exponential notation.y=exThis can also be written as:y=(ex)21
Find Derivative Using Chain Rule: Now, we need to find the derivative of y with respect to x. We will use the chain rule, which states that the derivative of a composite function is the derivative of the outer function evaluated at the inner function times the derivative of the inner function.dxdy=dxd[(ex)21]
Calculate Derivative of Outer Function: The outer function is the square root function, which can be written as a power of 21. The derivative of ab with respect to a is b⋅a(b−1), so the derivative of (ex)21 with respect to ex is 21⋅(ex)−21.dxdy=21⋅(ex)−21⋅dxd[ex]
Multiply Derivatives: The derivative of ex with respect to x is simply ex. So we multiply the derivative of the outer function by the derivative of the inner function.dxdy=21⋅(ex)−21⋅ex
Simplify Expression: Now, we simplify the expression. Since (ex)−21 is the same as ex1, we can rewrite the expression as:dxdy=21⋅ex1⋅ex
Further Simplification: We can simplify further by multiplying ex by the fraction. Since ex is the same as ex squared, we get:(dy)/(dx)=(1/2)⋅(ex/ex)
Divide and Simplify: Simplifying the expression by dividing ex by ex gives us ex, so we have:dxdy=21⋅ex
Verify Correct Answer: Finally, we can see that the correct answer matches option (A): dxdy=2ex
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