Multiply. 10x^(2)(-9x^(2)+10 x) Answer:

Distribute term 10x^2: Distribute the term 10x^2 across the terms inside the parentheses. We apply the distributive property a(b + c) = ab + ac. 10x^2 * (-9x^2) + 10x^2 * 10xMultiply first set of terms: Multiply the first set of terms. 10x^2 * (-9x^2) = -90x^(2+2) = -90x^4 We add the exponents when multiplying terms with the same base.Multiply second set of terms: Multiply the second set of terms. 10x^2 * 10x = 100x^(2+1) = 100x^3 Again, we add the exponents when multiplying terms with the same base.Combine results: Combine the results from Step 2 and Step 3. The final expression is -90x^4 + 100x^3.

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Multiply.

10x^(2)(-9x^(2)+10 x)
Answer:

Multiply. $\newline$ $10 x^{2}\left(-9 x^{2}+10 x\right)$ $\newline$ Answer:

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Precalculus

Operations with rational exponents

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Q. Multiply.

\newline

10 x^{2}\left(-9 x^{2}+10 x\right)

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Answer:

Distribute term $10x^2$ : Distribute the term $10x^2$ across the terms inside the parentheses. $\newline$ We apply the distributive property $a(b + c) = ab + ac$ . $\newline$ $10x^2 * (-9x^2) + 10x^2 * 10x$
Multiply first set of terms: Multiply the first set of terms. $10x^2 \times (-9x^2) = -90x^{(2+2)} = -90x^4$ We add the exponents when multiplying terms with the same base.
Multiply second set of terms: Multiply the second set of terms. $10x^2 \times 10x = 100x^{2+1} = 100x^3$ Again, we add the exponents when multiplying terms with the same base.
Combine results: Combine the results from Step $2$ and Step $3$ . $\newline$ The final expression is $-90x^4 + 100x^3$ .