Mabel was asked whether the following equation is an identity:(4x−3)(x−2)2=4x3−19x2+4x−12She performed the following steps:(4x−3)(x−2)2↪ Step 1=(4x−3)(x−2)(x−2)↪ Step 2=(4x−3)(x2−2x−2x+4)↪ Step 3=(4x−3)(x2−4x+4)↪ Step 4=4x3−16x2+16x−3x2−12x−12↪ Step 5=4x3−19x2+4x−12For this reason, Mabel stated that the equation is a true identity.Is Mabel correct? If not, in which step did she make a mistake?Choose 1 answer:(A) Mabel is correct.(B) Mabel is incorrect. She made a mistake in step 2.(C) Mabel is incorrect. She made a mistake in step 3.(D) Mabel is incorrect. She made a mistake in step 4.
Q. Mabel was asked whether the following equation is an identity:(4x−3)(x−2)2=4x3−19x2+4x−12She performed the following steps:(4x−3)(x−2)2↪ Step 1=(4x−3)(x−2)(x−2)↪ Step 2=(4x−3)(x2−2x−2x+4)↪ Step 3=(4x−3)(x2−4x+4)↪ Step 4=4x3−16x2+16x−3x2−12x−12↪ Step 5=4x3−19x2+4x−12For this reason, Mabel stated that the equation is a true identity.Is Mabel correct? If not, in which step did she make a mistake?Choose 1 answer:(A) Mabel is correct.(B) Mabel is incorrect. She made a mistake in step 2.(C) Mabel is incorrect. She made a mistake in step 3.(D) Mabel is incorrect. She made a mistake in step 4.
Expand Binomial 1: Expand the first binomial.(4x−3)(x−2)(x−2)
Expand Binomial 2: Expand the second binomial.(4x−3)(x2−2x−2x+4)Oops, made a mistake here. It should be (4x−3)(x2−2x−2x+4)=(4x−3)(x2−4x+4)
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