Problem statement: We are asked to find the logarithm of 49 with base 7, which is written as log₇(49). To solve this, we need to find the power to which the base 7 must be raised to get 49. We know that 7 squared (7^2) equals 49.Step 1: Therefore, log₇(49) is the exponent that we put on 7 to get 49, which we have determined to be 2. So, log₇(49) = 2.

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$\log _{7} 49=$

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Grade 8

Relationship between squares and square roots

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\log _{7} 49=

Problem statement: We are asked to find the logarithm of $49$ with base $7$ , which is written as $\log_7(49)$ . $\newline$ To solve this, we need to find the power to which the base $7$ must be raised to get $49$ . $\newline$ We know that $7$ squared ( $7^2$ ) equals $49$ .
Step $1$ : Therefore, $\log_7(49)$ is the exponent that we put on $7$ to get $49$ , which we have determined to be $2$ . $\newline$ So, $\log_7(49) = 2$ .